 | Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 446 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...dividend by the first term on the left of the divisor, and the first term of the quotient is found ; multiply the divisor by this term, and subtract the product from the dividend. Divide the first term of this remainder by the first term of the divisor, and the second... | |
 | Charles Davies - Algebra - 1835 - 378 pages
...division polynomials we have the following RULE. on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the fast term of the divisor, which gives... | |
 | Mathematics - 1836 - 530 pages
...divide the first term in the dividend by the first in the divisor, and write the result as the first in the quotient ; multiply the divisor by this term, and subtract the product from the di6 a 6s + б Ь3 vidend ; proceed to deal with the remainder, if any, in the same way. 43. By applying... | |
 | Algebra - 1838 - 372 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Charles Davies - Algebra - 1839 - 272 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Andrew Bell (writer on mathematics.) - 1839 - 500 pages
...rest in order. Divide the first term of the dividend by that of the divisor, the result is the first term of the quotient. Multiply the divisor by this term, and subtract the product from the dividend. Consider the remainder as a new dividend, arrange its terms, and proceed as before ; and... | |
 | Charles Davies - Algebra - 1842 - 368 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | George Roberts Perkins - Algebra - 1842 - 370 pages
...on. the left of the dividend by thefirst term on the left .of the divisor, the result is the first term of the quotient; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
 | Charles Davies - Algebra - 1842 - 284 pages
...term on the left of the dividend by the first term on the left of the divisor, the result is ike first term of the quotient ; multiply the divisor by this term, and subtract the product from the dividend. II. Then divide the first term of the remainder by the first term of the divisor, which gives... | |
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... the first term of the quotient ; multiply the• divisor by this term, and subtract the product from the dividend. 
