## Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with Explanatory Notes; a Series of Questions on Each Book; and a Selection of Geometrical Exercises from the Senate-house and College Examination Papers, with Hints, &c. Designed for the Use of the Junior Classes in Public and Private Schools. the first six books, and the portions of the eleventh and twelfth books read at CambridgeLongman, Green, Longman, Roberts, and Green, 1868 - 410 pages |

### From inside the book

Results 1-5 of 100

Page 7

...

...

**AC is equal**to AB ; ( def . 15. ) and because the point B is the center of the circle ACE , therefore BC is equal to AB ; but it has been proved that**AC is equal**to AB ; therefore AC , BC are each of them equal to AB ; but things which are ... Page 8

... equal to BC . Because the point B is the center of the circle CGH , therefore BC is equal to BG ; ( def . 15. ) and ...

... equal to BC . Because the point B is the center of the circle CGH , therefore BC is equal to BG ; ( def . 15. ) and ...

**AC equal**to the two sides DE , DF , each to each , viz . AB to DE , and AC to DF , and the included angle BAC equal ... Page 9

... equal to DE ; and AB coinciding with DE , the straight line AC shall fall on DF , because the angle BAC is equal to the angle EDF ; therefore also the point C shall coincide with the point F , because

... equal to DE ; and AB coinciding with DE , the straight line AC shall fall on DF , because the angle BAC is equal to the angle EDF ; therefore also the point C shall coincide with the point F , because

**AC is equal**to DF ; but the point B ... Page 10

...

...

**equal**to the base GB , ( 1. 4. ) and the triangle AFC is**equal**to the triangle AGB , also the remaining angles of the one are**equal**to the remaining angles of the other , each to each , to which the ...**equal**to**AC**, 10 EUCLID'S ELEMENTS . Page 11

...

...

**equal**to**AC**, one of them is greater than the other . If possible , let AB be greater than**AC**; and from BA cut off BD**equal**to CA the less , ( 1. 3. ) and join DC . Then , in the triangles DBC , ABC , because DB is**equal**to**AC**, and BC ...### Common terms and phrases

A₁ ABCD AC is equal Algebraically angle ABC angle ACB angle BAC Apply Euc base BC chord circle ABC constr demonstrated describe a circle diagonals diameter divided double draw equal angles equiangular equilateral triangle equimultiples Euclid exterior angle Geometrical given circle given line given point given straight line gnomon greater hypotenuse inscribed intersection isosceles triangle less Let ABC line BC lines be drawn multiple opposite angles parallelogram parallelopiped pentagon perpendicular plane polygon problem produced Prop proportionals proved Q.E.D. PROPOSITION quadrilateral figure radius ratio rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn similar similar triangles solid angle square on AC tangent THEOREM touch the circle trapezium triangle ABC twice the rectangle vertex vertical angle wherefore

### Popular passages

Page 6 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...

Page 118 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.

Page 2 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.

Page 317 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Page 90 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C; the squares of AB, BC are equal to twice the rectangle AB, BC, together with the square of AC.

Page 88 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.

Page 30 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 9 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.

Page 22 - IF two triangles have two sides of the one equal to two sides of the other, each to each, but the angle contained by the two sides of one of them greater than the angle contained by the two sides equal to them, of the other ; the base of that which has the greater angle shall be greater than the base of the other...

Page 92 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...