Modern Methods in Elementary Geometry |
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Page 19
... equal must be equally distant from the perpendicular . Therefore BC = B'C ' , and the triangles are congruent . PARALLELOGRAMS . A Parallelogram is a four - sided figure which has its opposite sides parallel . THEOREM XVI . The opposite ...
... equal must be equally distant from the perpendicular . Therefore BC = B'C ' , and the triangles are congruent . PARALLELOGRAMS . A Parallelogram is a four - sided figure which has its opposite sides parallel . THEOREM XVI . The opposite ...
Page 21
... equally distant from A and from B. For if P be any point on CD , and PA , PB be joined , these lines must be equal , being equally remote from the perpendicular . Also no point not on CD can be equally distant " 21 THE STRAIGHT LINE .
... equally distant from A and from B. For if P be any point on CD , and PA , PB be joined , these lines must be equal , being equally remote from the perpendicular . Also no point not on CD can be equally distant " 21 THE STRAIGHT LINE .
Page 22
E. M. Reynolds. Also no point not on CD can be equally distant from A and B. D F P E C Let F be any point not on CD . Join FA , FB ; let FA cut CD in E ; join EB . Then FB < FE + EB , but therefore EB = EA ; FB FA . Hence if we know of ...
E. M. Reynolds. Also no point not on CD can be equally distant from A and B. D F P E C Let F be any point not on CD . Join FA , FB ; let FA cut CD in E ; join EB . Then FB < FE + EB , but therefore EB = EA ; FB FA . Hence if we know of ...
Page 23
... equally distant from AB and from AC . Let G be a point not on AD . Let fall GE , GH perpendicular to AB , AC . And ... equally distant from AB and from AC . If AD be equally distant from AB and AC , the distance being measured by ...
... equally distant from AB and from AC . Let G be a point not on AD . Let fall GE , GH perpendicular to AB , AC . And ... equally distant from AB and from AC . If AD be equally distant from AB and AC , the distance being measured by ...
Page 25
... equally distant from B and C. [ I. 19 . And since O is a point on EH , it is equally distant from C and A. Therefore O is equally distant from B and A. Therefore is a point on FK . That is , FK passes through 0 . [ I. 19 . [ I. 19 ...
... equally distant from B and C. [ I. 19 . And since O is a point on EH , it is equally distant from C and A. Therefore O is equally distant from B and A. Therefore is a point on FK . That is , FK passes through 0 . [ I. 19 . [ I. 19 ...
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Common terms and phrases
Algebra alternate angle altitude ARITHMETIC base BC² BEGINNERS bisect BROOKE FOSS WESTCOTT Cambridge centre chord Christ's College circle touching circumference Clifton College cloth coincide congruent CONIC SECTIONS construct contains convex angle Crown 8vo describe a circle diagonals diameter dicular distance divide Edward Thring ELEMENTARY TREATISE equal angles equally distant equiangular equilateral triangle Examination Papers Exercises exterior angle Fcap Fellow of St GEOMETRY given circle given line given point given square given straight line greater Greek Text Head Master Hence inscribe intersect John's College Join JOSEPH WOLSTENHOLME Jugurtha late Fellow Latin Let ABCD line drawn locus Mathematical Lecturer measure meet middle point MIXED MATHEMATICS numerous parallel to BC parallelogram perpen perpendicular polygon problems quadrilateral figure radius rectangle right angles Second Edition Shew similar triangles student tangent THEOREM VII Third Edition trapezium triangle ABC vertex
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