 | Ormsby MacKnight Mitchel - Algebra - 1845 - 308 pages
...the product of the first term of the root, by the second term, plus the square of the second term. Multiply the complete divisor by the second term of the root, and subtract the product from the remainder, and bring down the next remainder. Divide the first term of this remainder... | |
 | Rufus Putnam - Arithmetic - 1849 - 276 pages
...multiplied by the figure last placed in the root, and the square of this last figure, and add them to the trial divisor, for a complete divisor. Multiply the complete divisor by the last figure in the root ; subtract the product from the dividend ; bring down the next period, and... | |
 | Daniel Leach - Arithmetic - 1851 - 280 pages
...partial dividend, omitting the right hand figure, and write the result in the quotient, and also annex it to the trial divisor for a complete divisor. Multiply the complete divisor by the last figure, and subtract the product from the partial dividend, and to the remainder annex the next... | |
 | Daniel Leach - Arithmetic - 1853 - 622 pages
...dividend, omitting the right hand figure, and icrite the result in the quotient, and also annex it to the trial divisor for a complete divisor. Multiply the. complete divisor by the last figure, and subtract the product from the partial dividend, and to the remainder annex the next... | |
 | Theodore Strong - Algebra - 1859 - 570 pages
...the root, and annex the second term of the root to the incomplete divisor, and the result will be the complete divisor. Multiply the complete divisor by the second term of the root, and subtract the product from the first remainder, cutid the result will constitute the second remainder. 3. Take... | |
 | Horatio Nelson Robinson - Arithmetic - 1859 - 362 pages
...divisor, and write the quotient for a trial figure in the root. IV. Add the trial figure of the root to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, and subtract the product from the dividend, and to the remainder bring down... | |
 | Horatio Nelson Robinson - Algebra - 1863 - 432 pages
...divisor, and write the quotient for a triai figure in the root. IV. Annex the trial figure of the root to the trial divisor for a complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the remainder bring... | |
 | Horatio Nelson Robinson - Algebra - 1864 - 444 pages
...divisor, and write the quotient for a trial figure in the root. IV. Annex the trial figure of (lie root to the trial divisor for a complete divisor ; multiply the complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the... | |
 | Daniel Barnard Hagar - Algebra - 1873 - 278 pages
...of the remainder by double the root already found, and annex the result to the root, and also to the divisor, for a complete divisor. Multiply the complete...divisor by the second term of the root, and subtract the product from the dividend. Continue the process, if there are other terms, as before. PROBLEMS.... | |
 | Joseph Ficklin - Algebra - 1874 - 446 pages
...of the root, also the square of the second term; the result will be the first complete divisor. IV. Multiply the complete divisor by the second term of the root, and subtract the product from the first remainder. V. Divide the first term of the second remainder by the par~... | |
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Add the trial figure of the root to the trial divisor for a complete divisor; multiply the complete divisor by the... 
