Stoddard's Practical Arithmetic

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Sheldon & Company, 1852 - Arithmetic - 299 pages
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Page 188 - If the payment be less than the Interest, the surplus of interest must not be taken to augment the principal ; but interest continues on the former principal until the period when the payments, taken together, exceed the interest due...
Page 85 - TIME 60 seconds (sec.) = 1 minute (min.) 60 minutes = 1 hour (hr.) 24 hours = 1 day...
Page 79 - Weight is used in weighing groceries ana all coarse articles ; as, sugar, tea, coffee, butter, cheese, flour, hay; &c., and all metals except gold and silver. 16 drams (dr.) make 1 ounce, marked oz. 16 ounces " 1 pound, " Ib. 25 pounds " 1 quarter, " qr. 4 quarters, or 100 Ibs. " 1 hundred weight, " cwt. 20 hundred weight " 1 ton,
Page 6 - Romans, employs in expressing numbers seven capital letters, viz. : I for one ; V for five ; X for ten ; L for fifty ; C for one hundred ; D for five hundred ; M for one thousand.
Page 185 - Given the principal, the time, and the interest, to find the rate per cent. RULE. Divide the given interest by the interest of the given principal, for the given time, at one per cent.
Page 63 - Place the sum down as in the last example, then mark off from the right of the dividend as many figures as there are ciphers in the divisor...
Page 113 - RULE. — Multiply all the numerators together for a new numerator, and all the denominators for a new denominator ; then reduce the new fraction to its lowest terms.
Page 273 - A person looking on his watch, was asked, what was the time of the .day ; he answered, it is between 4 and 5 ; but A more particular answer being required, he said, that the hour and minute hands were then exactly together.
Page 188 - The rule for casting interest, when partial payments have been made, is to apply the payment, in the first place, to the discharge of the interest then due. If the payment exceeds the interest, the surplus goes towards discharging the principal, and the subsequent interest is to be computed on the balance of principal remaining due.
Page 229 - Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required.

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