The Elements of Euclid, the parts read in the University of Cambridge [book 1-6 and parts of book 11,12] with geometrical problems, by J.W. Colenso1846 |
From inside the book
Page 37
... parallelo- gram ; and EBCA is equal to DBCF , B C F because they are upon the same base BC , and between the same parallels BC , EF ( 1.35 ) : But the triangle E ABC is half of the parallelogram EBCA , because the BOOK 1 . 37.
... parallelo- gram ; and EBCA is equal to DBCF , B C F because they are upon the same base BC , and between the same parallels BC , EF ( 1.35 ) : But the triangle E ABC is half of the parallelogram EBCA , because the BOOK 1 . 37.
Page 38
... half of the parallelogram GBCA , because the diameter AB bisects it ( 1. 34 ) ; and the triangle DEF is half of the parallelogram DEFH , because the diameter DF bisects it : But the halves of equal things are equal ; therefore the ...
... half of the parallelogram GBCA , because the diameter AB bisects it ( 1. 34 ) ; and the triangle DEF is half of the parallelogram DEFH , because the diameter DF bisects it : But the halves of equal things are equal ; therefore the ...
Page 54
... equal . 71. The area of a trapezium is half that of a pa- rallelogram , whose base is the sum of the two parallel sides , and altitude the perpendicular distance between them . 72. On the sides AB , AC of a triangle 54 PROBLEMS .
... equal . 71. The area of a trapezium is half that of a pa- rallelogram , whose base is the sum of the two parallel sides , and altitude the perpendicular distance between them . 72. On the sides AB , AC of a triangle 54 PROBLEMS .
Page 55
... half of AC : if through B , C , parallel lines be drawn , cutting any other line through A in D , E , then AD is half of AE , and BD of CE , and the triangle ABD a fourth of the triangle ACE ; and , conversely , if BD be such that AD is ...
... half of AC : if through B , C , parallel lines be drawn , cutting any other line through A in D , E , then AD is half of AE , and BD of CE , and the triangle ABD a fourth of the triangle ACE ; and , conversely , if BD be such that AD is ...
Page 56
... half the original figure shew also that the lines joining the bisections of opposite sides bisect each other . 83. Through D , E , the bisections of the sides AB , AC of a triangle , draw DF , EF parallel to BE , AB ; and shew that the ...
... half the original figure shew also that the lines joining the bisections of opposite sides bisect each other . 83. Through D , E , the bisections of the sides AB , AC of a triangle , draw DF , EF parallel to BE , AB ; and shew that the ...
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The Elements of Euclid, the Parts Read in the University of Cambridge [Book ... Euclides No preview available - 2016 |
Common terms and phrases
ABCD adjacent angles angle ABC angle ACB angle BAC angle BCD angle EDF angle equal base BC BC is equal centre chord circle ABC circumference cuts the circle diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given straight line gnomon greater ratio inscribed intersection isosceles triangle less Let ABC Let the straight lines be drawn lines drawn meet multiple opposite angles opposite sides parallel to BC parallelogram pentagon perpendicular plane polygon PROB produced proportionals Q.E.D. PROP rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn square of AC straight line &c straight line AB THEOR touches the circle triangle ABC twice the rectangle Wherefore
Popular passages
Page 42 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 4 - Let it be granted that a straight line may be drawn from any one point to any other point.
Page 33 - F, which is the common vertex of the triangles: that is », together with four right angles. Therefore all the angles of the figure, together with four right angles are equal to twice as many right angles as the figure has sides.
Page 62 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Page 22 - If from the ends of a side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than the other two sides of the triangle, but shall contain a greater angle.
Page 58 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Page 146 - ... may be demonstrated from what has been said of the pentagon : and likewise a circle may be inscribed in a given equilateral and equiangular hexagon, and circumscribed about it, by a method like to that used for the pentagon.
Page 194 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Page 69 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.