THE ROOT OF ANY MONOMIAL. Extract the root of the numerical coefficient, and divide the exponent of each literal factor by the number which marks the degree of the root. The roason for this rule is manifest, since extracting a root is the reverse of finding... Common School Algebra - Page 191by Thomas Sherwin - 1855 - 238 pagesFull view - About this book
| Thomas Sherwin - Algebra - 1841 - 314 pages
...method given in Art. 1O»>, for obtaining powers of monomials, results the following RULE FOR FINDING THE ROOT OF ANY MONOMIAL. Extract the root of the...number which marks the degree of the root. The reason for this rule is manifest, since extracting a root is the reverse of finding a power. Thus, the second... | |
| Thomas Sherwin - Algebra - 1841 - 320 pages
...method given in Art. 1O.», for obtaining powers of monomials, results the following RULE FOR FINDING THE ROOT OF ANY MONOMIAL. Extract the root of the...the number which marks the degree of the root. The roason for this rule is manifest, since extracting a root is the reverse of finding a power. Thus,... | |
| Thomas Sherwin - Algebra - 1856 - 318 pages
...given in Art. 105, for obtaining powers of monomials, results the following RULE FOR FINDING THE HOOT OF ANY MONOMIAL. Extract the root of the numerical...number which marks the degree of the root. The reason for this rule is manifest, since extracting a root is the reverse of finding a power. Thus, the second... | |
| Thomas Sherwin - 1862 - 252 pages
...a + 6 -|_ c )4 — a 4 _f- 4 a3 j 4_ 4 a3 c _f- 6 a 2 62 _f- 12 SECTION XXXVI. ROOTS OF MONOMIALS. RULE FOR EXTRACTING THE ROOT OF ANY MONOMIAL. Extract...coefficient, and divide the exponent of each literal factSr by the number which marks the degree of the root. The reason of this rule is manifest, as may... | |
| Thomas Sherwin - 1864 - 260 pages
...6 6 2 c 2 + 4 6 c 3 + c 4 . SECTION XXXVI. ROOTS OF MONOMIALS. RULE FOR EXTRACTING THE ROOT OF AN\ MONOMIAL. Extract the root of the numerical coefficient,...be shown by an example. Thus, the second power of 3 z y * is 9 z!x 2y2x2 — 922y4. consequently, the second root of — 3 T* y* = 3 xy*. In like manner,... | |
| Thomas Sherwin - 1865 - 260 pages
...-J- c )4 — a 4 -f 4 a 3 6 _(- 4 a 3 c -fga 2 6 2 + 12 « 2 6 c + SECTION XXXVI. ROOTS OF MONOMIALS. RULE FOR EXTRACTING THE ROOT OF ANY MONOMIAL. Extract...be shown by an example. Thus, the second power of 3 x y 2 is 9 x l * 2 y2 * % = 9 x z y 4 ; consequently, the second root of 9 x* y 4 = 3 z- y* = 3 x... | |
| Elias Loomis - Algebra - 1868 - 386 pages
...letters by the exponent of the power required. Hence, conversely, to extract any root of a monomial, we extract the root of the numerical coefficient, and divide the exponent of each letter by the index of the required root. e Thus the cube root of 64a 6 6 3 is 4a*Z>. 195. Sign of... | |
| Elias Loomis - Algebra - 1873 - 396 pages
...letters by the exponent of the power required. Hence, conversely, to extract any root of a monomial, we extract the root of the numerical coefficient, and divide the exponent of each letter by the index of the required root. Thus the cube root of 64a663 is 4a25. 195. Sign of the Boot.... | |
| Edwin Pliny Seaver, George Augustus Walton - Algebra - 1881 - 304 pages
...found by reversing the operation described in Art. 245. The method, therefore, is to find the n th root of the numerical co-efficient, and divide the exponent of each literal factor byn. This may be expressed by the formula where A stands for the numerical co-efficient, and x p ,... | |
| Algebra - 1888 - 492 pages
...the cube root of — 8a2ô6c9. EVOLUTION. 4 / 16a4¿>8 __ V 8lжy2 — Rule. — I. Take the required root of the numerical coefficient, and divide the exponent of each literal factor by the index of the root. II. Give the double sign ± to an even root of a positive quantity, and to an odd... | |
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