 The area of a trapezoid is equal to one-half the product of the altitude and the sum of the bases. THEOREM 116. Two parallelograms or two triangles are equivalent if 1. They have equal bases and are between the same parallels. 2. a = a  Plane Geometry - Page 198by Mabel Sykes, Clarence Elmer Comstock - 1918 - 322 pagesFull view - About this book
 | Alfred Hix Welsh - Geometry - 1883 - 326 pages
...of the vertices of all the triangles of constant area on either side of a given base. THEOREM VII. The area of a trapezoid is equal to one-half the product of its altitude by the sum of its parallel sides. Let ABCD be a trapezoid, whose altitude is a, and .whose... | |
 | Trinity College (Hartford, Conn.) - 1888 - 978 pages
...intercepted arc. 5. The area of a parallelogram is equal to the product of its base and altitude. 6. The area of a trapezoid is equal to one-half the product of its nltitiule and the sum of its parallel sides. 7. If the radius of a circle is divided in extreme... | |
 | William Shaffer Hall - Measurement - 1893 - 88 pages
...altitude. For Proof: See Ww. Geom., 321. §. 24. To find the area of a trapezoid. [15] RULE: The area is equal to one-half the product of the altitude and the sum of the parallel sides. For Proof: See Ww. Geom., 327. § 25. To find the area of a parallelogram when two... | |
 | George Clinton Shutts - Geometry - 1894 - 412 pages
...product of the base and altitude," in propositions IV and V, see § 329. PROPOSITION VI. 335. Theorem. The area of a trapezoid is equal to onehalf the product of its altitude and the sum of its bases. AB " M Let AB С D represent a trapezoid, and AM its altitude.... | |
 | Silas Ellsworth Coleman - Arithmetic - 1897 - 180 pages
...parallel sides of a trapezoid are called the bases ; and the distance between them is the altitude. The area of a trapezoid is equal to one-half the product of the altitude and the sum of the bases. EXPLANATION. Draw a diagonal. This divides the trapezoid . into two triangles whose common altitude... | |
 | Silas Ellsworth Coleman - Arithmetic - 1897 - 178 pages
...trapezoid are called the bases; and the distance between them is the altitude. The area of a trapexoid is equal to one-half the product of the altitude and the sum of the bases. -. i •> : f«l»i + HJ Draw a diagonal. This divides the trapezoid into two triangles whose common... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 396 pages
...triangle. Ex. 798. To transform a trapezoid into an isosceles triangle. PROPOSITION VII. THEOREM 354. The area of a trapezoid is equal to one.half the product of its altitude and the sum of its bases. Hyp. Trapezoid ABCD has the bases b and c respectively, and... | |
 | Arthur Schultze - 1901 - 260 pages
...process until a triangle is obtained. [The proof is left to the student.] PROPOSITION VII. THEOREM 354. The area of a trapezoid is equal to one.half the product of its altitude and the sum of its bases. Hyp. Trapezoid ABCD has the bases b and c respectively, and... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...process until a triangle is obtained. [The proof is left to the student.] PROPOSITION VII. THEOREM 354. The area of a trapezoid is equal to one-half the product of its altitude and the sum of its bases. Hyp. Trapezoid ABCD has the bases b and c respectively, and... | |
 | Metal-work - 1901 - 548 pages
...= 84 ; therefore, 4/705,600 = 840. Thus, the area is 840 sq. in. Ans. 64. Area of a Trapcznld. — The area of a trapezoid is equal to one-half the product of its altitude and the sum of its parallel sides. The diagonal AC divides the trapezoid ABCD, Fig. 9,... | |
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