 The perpendicular bisectors of the sides of a triangle are concurrent at a point which is equally distant from the vertices.  Plane Geometry - Page 193by Mabel Sykes, Clarence Elmer Comstock - 1918 - 322 pagesFull view - About this book
 | William Herschel Bruce, Claude Carr Cody (Jr.) - Geometry, Modern - 1910 - 286 pages
...three. PROPOSITION LI. THEOREM. 205. The medians of a triangle are concurrent in a point two thirds the distance from each vertex to the mid-point of the opposite side. Given the A ABC. To prove the medians AF, BG, and CH are concurrent in a point two thirds the distance... | |
 | John Wesley Young, Albert John Schwartz - Geometry, Modern - 1915 - 250 pages
...complete the proof.) 254. THEOREM. The medians of a triangle meet in a point which is two thirds of the distance from each vertex to the mid-point of the opposite side. A BFC FIG. 115. Given the triangle ABC with medians BE and CD meeting in 0. To prove that the third... | |
 | Webster Wells, Walter Wilson Hart - Geometry, Plane - 1915 - 330 pages
...from C to .F. On AD, this is point 0. 10. Hence the three medians meet at point 0, which is two thirds the distance from each vertex to the mid-point of the opposite side. Note. — The point of intersection of the medians of a triangle is called the Center of Gravity of... | |
 | Webster Wells, Walter Wilson Hart - Geometry - 1916 - 504 pages
...from C to F. On AD, this is point 0. 10. Hence the three medians meet at point 0, which is two thirds the distance from each vertex to the mid-point of the opposite side. Exercises Solved by Indirect Proofs Ex. 192. If two straight lines are cut by a transversal, and a... | |
 | Norwood Press - Printers - 1916 - 470 pages
...complete the proof.) 254. THEOREM. The medians of a triangle meet in a point which is two thirds of the distance from each vertex to the mid-point of the opposite side. Fio. 115. Given the triangle ABC with medians BE and CD meeting in 0. To prove that the third median... | |
 | George Wentworth, David Eugene Smith, Joseph Clifton Brown - Mathematics - 1918 - 300 pages
...vertices of a triangle to the mid-points of the opposite sides are concurrent in a point two thirds of the distance from each vertex to the mid-point of the opposite side. Two such lines, as AQ and CP, meet as at O. If Y is the mid-point of A 0, and X the mid-point of CO,... | |
 | Mabel Sykes, Clarence Elmer Comstock - Geometry, Solid - 1922 - 236 pages
...the sides of the angle. THEOREM 86. The perpendicular bisector of a segment is the locus of a point equally distant from the ends of the segment. COR....dividing both terms of a ratio by the same number does not change the value of the ratio. As. 57. Ratios equal to the same ratio are equal. As. 58. Equal... | |
 | Mabel Sykes, Clarence Elmer Comstock - Geometry, Solid - 1922 - 236 pages
...THEOREM 86. The perpendicular bisector of a segment is the locus of a point equally distant from the ends of the segment. THEOREM 87. The perpendicular bisectors...dividing both terms of a ratio by the same number does not change the value of the ratio. As. 57. Ratios equal to the same ratio are equal. As. 58. Equal... | |
 | Raleigh Schorling, William David Reeve - Mathematics - 1922 - 476 pages
...or AO=\AL, and BO = IBM. 11. In like manner, AL and CN intersect in a point which is two thirds of the distance from each vertex to the midpoint of the opposite side. In other words, CN also passes through O. 12. ••• the medians of a triangle are concurrent in... | |
 | David Eugene Smith - Geometry, Plane - 1923 - 314 pages
...medians (§ 132) of a triangle. Theorem. The medians of a triangle meet in a point which is two thirds of the distance from each vertex to the midpoint of the opposite side. In giving the proof let any two medians, as AQ and CP, meet as at O. Then if Y is the midpoint of^4O... | |
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