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" Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the letters of the divisor from the dividend. "
An Introduction to Algebra Upon the Inductive Method of Instruction - Page 81
by Warren Colburn - 1831 - 276 pages
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - Algebra - 1825 - 400 pages
...If 6 a 6 c be divided into 2 a parts, what is one of the parts ? Ans. 3 bc ; because 2 a times 3 bc is 6 ab c. Hence we derive the following RULE. Divide...the coefficient of the divisor, and strike out the lettert of the divisor from the dividend. 3. Divide 16 a be by 4. 4. " 12a6c by 3 a. 5. " 20a6c by...
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - Algebra - 1826 - 290 pages
...because 3 bc times 2 a is 6 ab c. 2. If 6 abc be divided into 2 a parts, what is one of the parts ? Hence we derive the following RULE. Divide the coefficient...letters of the divisor from the dividend. 3. Divide 16 abc by 4. 4. " 12a6c -by 3a. 5. " 20a6c by 10 be. 6. " 18 abed by Gad. 7. " 23a6c by o6. 8. " 17...
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - Algebra - 1828 - 288 pages
...because 3 bc times 2 a is 6 ab c. 2. If 6 abc be divided into 2 a parts, what is one of the parts f Hence we derive the following RULE. Divide the coefficient...divisor from the dividend. 3. Divide 16a6c by 4. 4. " 12 abc by 3 a. 5. " 20abc by 10 b c. 6. " 18 abcd by 6 ad. 7. " 23 abc by a b. 8. " IT ad by a d....
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - Algebra - 1828 - 292 pages
...one of the parts ? Am. 3 bc ; because 2 a times 3 bc is 6 ab c. Hence we derive the following RCL.E. Divide the coefficient of the dividend by the coefficient...letters of the divisor from the dividend. 3. Divide 1 6 abc by 4. 4. " 12abc by 3 a. 5. " 20a6c by 10 6 c. 6. « 18 a 6ed by 6 ad. 7. " 23a6c by a b. 8....
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The student's algebra

John Darby (teacher of mathematics.) - 1829 - 212 pages
...Multiplication, and is commonly divided into three cases. CASE I. When the quantities are both simple. RULE. — Divide the coefficient of the dividend, by the coefficient of the divisor, to obtain the coefficient of the quotient ; expunge the letters which are common to both quantities,...
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - Algebra - 1830 - 288 pages
...derive' the following RULE. Divide tJie coefficient of the dividend by the coefficient of the divism; and strike out the letters of the divisor from the dividend. 3. Divide 16a6c by 4. 4. " 12a6c by So. 5. " 20a6c by 10 be. 6. " 18 a 6 erf by 6arf. 7. " 23a6c by ab. 8. " 17 ad by a d. 9....
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Elements of Algebra

William Smyth - Algebra - 1830 - 278 pages
...From what has been said we have the following rule for the division of simple quantities, viz. 1°. divide the coefficient of the dividend by the coefficient of the divisor; 2°. suppress in the dividend the letters, which are common to it and the divisor, when they have the...
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Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ...

Charles Davies - Algebra - 1835 - 378 pages
...Also1 for, 7ai x 5a'ic = 35a^c. 50. Hence for the division of monomials we have the following RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor. II. Write in tJie quotient, after the co-efficient, all the tellers common to tlie dividend and divisor,...
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A New Introduction to the Science of Algebra ...

Silas Totten - Algebra - 1836 - 320 pages
...therefore, only to reverse the rule for multiplication. For the division of monomials, we have thc'n the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and to the quotient annex the letters common fo both, each affected wit'i an exponent equal to the difference...
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A New Introduction to the Science of Algebra ...

Silas Totten - Algebra - 1836 - 332 pages
...to reverse the rule for multiplication. For the division of monomials, we have then the following i RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and to the quotient annex the letters common to both, each affected wit,1 an exponent eqiial>to the difference...
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