Elements of Geometry and Trigonometry: With Applications in Mensuration |
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Page 12
... suppose the circumference of a circle to be divided into 360 degrees , beginning at the point B. If through the point of division marked 40 , we draw CE , then , the angle ECB will be equal to 40 degrees . If CF were drawn through 180 ...
... suppose the circumference of a circle to be divided into 360 degrees , beginning at the point B. If through the point of division marked 40 , we draw CE , then , the angle ECB will be equal to 40 degrees . If CF were drawn through 180 ...
Page 17
... suppose the part AEB to be turn- ed around AB , until it shall fall on the part ADB . The curve AEB will then exactly coincide with the curve ADB , or else there would be some point in the curve AEB or ADB , unequally distant from the ...
... suppose the part AEB to be turn- ed around AB , until it shall fall on the part ADB . The curve AEB will then exactly coincide with the curve ADB , or else there would be some point in the curve AEB or ADB , unequally distant from the ...
Page 18
... suppose a semicircum ' erence to be described . Then , the angle.DCI will be measured by the arc BD , and the angle DCA by the arc AD . But the sum of the two arcs is equal to a semicir- cumference : hence , the sum of the two angles is ...
... suppose a semicircum ' erence to be described . Then , the angle.DCI will be measured by the arc BD , and the angle DCA by the arc AD . But the sum of the two arcs is equal to a semicir- cumference : hence , the sum of the two angles is ...
Page 19
... suppose the side AC , of the AA A B D triangle ACB , to be placed on DF , so that the extremity C shall fall on the extremity : then , since the sides are equal , will fall on ER But since the angle C is equal to the angle F , the line ...
... suppose the side AC , of the AA A B D triangle ACB , to be placed on DF , so that the extremity C shall fall on the extremity : then , since the sides are equal , will fall on ER But since the angle C is equal to the angle F , the line ...
Page 21
... suppose the line CD to be drawn dividing the angle C into two equal parts . Then , the two triangles ACD and DCB , have two sides and the included angle of the one equal to two sides and the in- cluded angle of the other , each to each ...
... suppose the line CD to be drawn dividing the angle C into two equal parts . Then , the two triangles ACD and DCB , have two sides and the included angle of the one equal to two sides and the in- cluded angle of the other , each to each ...
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Common terms and phrases
adjacent angles allel altitude angles equal bisect called centre chains chord circle whose diameter circumference column common comp cone consequently convex surface Cosine Cosine D Cotang cylinder Davies decimal diagonal dicular distance divided draw equal Bk equal to half equivalent figure find the area frustum greater half the arc half the product hence horizontal hypothenuse inches included angle inscribed intersection Let ABCD logarithm lower base M.
M. Sine measured by half Mensuration of Surfaces number of sides opposite angles outward angle parallel parallelogram parallelopipedon pendicular pentagonal pyramid perimeter perpen perpendicular plane prism PROBLEM proportion pyramid quadrilateral radii radius ratio rectangle regular polygon Required the area rhombus right angled triangle right angles Bk segment side AC similar similar triangles slant height solidity sphere straight line suppose Tang tangent THEOREM triangle ABC upper base yards