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" Arts. 200 and 201 we derive the following rule : Extract the required root of the numerical coefficient, and divide the exponent of each letter by the index of the root. "
College Algebra - Page 137
by Webster Wells - 1890 - 577 pages
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Elements of Algebra

William Smyth - Algebra - 1830 - 278 pages
...required. Thus a 3 raised to the third power Conversely to extract the root of a simple quantity, we divide the exponent of each letter by the index of the root. Thus The utility of exponents of the kind, which we are here considering, consists principally in this,...
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Elements of Algebra

Bourdon (M., Louis Pierre Marie) - Algebra - 1831 - 326 pages
...of a simple quantity to any degree whatever, we must (1.) extract the root of the coefficient, (2.) divide the exponent of each letter by the index of the root. Thus, 3 4 ^/64an3~c6 = 4a36c2; ^/l6«s6i2^ — 2a26*c. We see, according to this rule, that in order...
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Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ...

Charles Davies - Algebra - 1835 - 378 pages
...Extraction of Roots. 199. To extract the n" root of a monomial, follow the rule given in Art. 182, viz. divide the exponent of each letter by the index of the root. For, the exponent of each letter in the result should be such, that multiplied by n, the index of the...
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A New Introduction to the Science of Algebra...

Silas Totten - Algebra - 1836 - 360 pages
...Involve a * to the y power. ii t» vr a" ' = EXTRACTION OF ROOTS. RULE. (68.) Extract the root of the coefficient, and divide the exponent of each letter by the index of the required root. t. 2 1 Thus, the square root of a3 is or; and the cube root of a? is a* * = a* . EXAMPLES....
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Elements of Algebra

Charles Davies - Algebra - 1842 - 368 pages
...Hence, reciprocally, to extract any root of a monomial, 1st. Extract the root of the co-efficient. 2d. Divide the exponent of each letter by the index of the root. V64a 9 2rV=4a 3 Ac 3 ; Vl6a 8 i l V=2a 3 i 3 c. From this rule, we perceive, that in order that a monomial...
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Elements of Algebra: Including Sturms' Theorem

Charles Davies - Algebra - 1845 - 382 pages
...power, and unite the terms. Hence, to extract any root of a monomial, 1st. Extract the root of the co-efficient and divide the exponent of each letter by the index of the root. 2d. To the root of the coefficient annex each letter with its new exponent, and the result will be...
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An Elementary Treatise on Algebra: Theoretical and Practical ...

Horatio Nelson Robinson - Algebra - 1846 - 276 pages
...following RULE. For the extraction of the roots of monomials. Extract the root of the numeral 'coefficients and divide the exponent of each letter by the index of the root. EXAMPLES. 1. What is the square root of 49a3x4? Ans. lax3. 2. What is the square root of 25c'663? Ans.5csb....
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An Elementary Treatise on Algebra: Designed as First Lessons in that Science

Horatio Nelson Robinson - Algebra - 1850 - 256 pages
...factors. Thus the cube root of 8x2 is 2x. RULE . — Extract the root of the numeral coefficients, and divide the exponent of each letter by the index of the root. EXAMPLES. 1. What is the second root of 9o2aV ? , . Ans. 3aary. 2. What is the third root of 8aV ?...
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A Theoretical and Practical Treatise on Algebra: In which the Excellencies ...

Horatio Nelson Robinson - Algebra - 1850 - 358 pages
...following RULE. For the extraction of the roots of monomials. Extract the root of the numeral coefficients and divide the exponent of each letter by the index of the root. EXAMPLES. 1. What is the square root of 49a?x t ? Ans. 7aaf. 2. What is the square root of 25e I0 6...
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Treatise on Algebra, for the Use of Schools and Colleges

William Smyth - Algebra - 1855 - 370 pages
...power required. _2 Thus a raised to the third power Conversely, to extract the root of a monomial, we divide the exponent of each letter by the index of the root. Thus tfa-3 = a~3. The utility of exponents, of the kind which we are here considering, consists principally...
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