First Course in Algebra |
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a²b a²c a²x a²x² ab² ac² addition and subtraction algebra altitude arithmetic ax² base binomial cents Check coefficient decimal digits distance divided division divisor dollars equal example EXERCISES Solve exponent expression extracting the square factor feet Find the number Find the rate fractions graph greater number Hence HINT hypotenuse inches integers less letter linear equation method miles per hour minuend minus monomial Multiply negative numbers obtained ORAL EXERCISES parentheses perimeter polynomial positive number preceding problem proportion quadratic equation quotient radical radicand ratio rectangle remainder represent result right triangle Rule side Similarly simplify Solution square root Substituting symbols three numbers Transposing travels trial divisor trinomial twice unknown WILLIAM ROWAN HAMILTON Write x²y x³y xy² xy³ y-distance zero
Popular passages
Page 287 - If four quantities are in proportion, they are in proportion by composition ; that is, the sum of the first two . terms is to the second term as the sum of the last two terms is to the fourth term.
Page 109 - The product of two binomials having a common term equals the square of the common term, plus the algebraic sum of the unlike terms multiplied by the common term, plus the algebraic product of the unlike terms.
Page 290 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.
Page 75 - The Second Power of a number is the product obtained by using the number twice as a factor. Thus, 16 is the second power of 4, since 4x4-- 16.
Page 91 - Divide the first term of the dividend by the first term of the divisor.
Page 239 - В together can do a piece of work in 6 days, A and С in 8 days, and В and С in 12 days.
Page 280 - ... graphs of the quadratic equation and the linear equation may be approximated and their coordinates taken as solutions, since the points lie on both curves. The simplest algebraic method is carried out by eliminating one of the variables. More specifically, we solve the linear equation for one variable in terms of the other, substitute this value in the quadratic equation, and solve the resulting quadratic equation in one variable. With these results substituted in the original linear equation,...
Page 245 - See how many times this trial divisor is contained in all of the dividend, excepting the right hand figure, and write the quotient as the next figure of the root, and also place it at the right of the trial divisor, to form a true divisor.
Page 153 - Find the product of these factors, taking each factor the greatest number of times it occurs in any one of the given numbers.