 ... graphs of the quadratic equation and the linear equation may be approximated and their coordinates taken as solutions, since the points lie on both curves. The simplest algebraic method is carried out by eliminating one of the variables. More specifically,...  First Course in Algebra - Page 280by Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1917 - 309 pagesFull view - About this book
 | Louis Parker Jocelyn - Algebra - 1902 - 460 pages
...value of one of the unknown quantities in terms of the other unknown quantity and the known quantities. Substitute this value in the quadratic equation, and solve the resulting equation. Dem. of Rule. Let 1 . ax + by + <: = 0 be the linear equation, and 2. At? + 2 Hxy + Bf + 2 Gx + 2 Fy... | |
 | Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1918 - 298 pages
...for y in (1) and (2), 49 - 42 = 7, 7+ 6 =13. Substituting — £ for x and 6f for y in (1) and (2), EXERCISES Solve the following systems, pair results, and check each set of roots : ' 2. a? + f = 13. x2 - f = 8, = 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 4 s — 3 1 = 6. s2 - 3 st = 22,... | |
 | Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1919 - 536 pages
...The method of the preceding solution is stated in the Rule. Solve the linear equation for one unknown in terms of the other. Substitute this value in the...Solve the following systems, pair results, and check, mch , set of roots : f ~. " \ ' \ r *1 (, = 5, \ a:y =12, Vf. XN4*-3y = 30, X3"0> 2 J_ /2 — -1^ J... | |
 | Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - Algebra - 1926 - 456 pages
...quadratic and one linear equation is stated in the RULE. Solve the linear equation far one unknown in terms of the other. Substitute this value in the...two sets of roots of the simultaneous system. CHECK. Substitute as usual, in both equations. EXERCISES Solve the following systems, pair results, and check... | |
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