## A Treatise on Elementary and Higher Algebra |

### From inside the book

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**Unknown Letter**348 Solution of Two or More separate Simple Equations containing as CONTENTS . vii. Page 233

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**unknown letter**( or the independent variable ) which satisfy the equation , we perceive how we may ( often ) pro- ceed in order to find them . Thus , if we put a2 7x + 5 for X , and use 6 and 7 for a and b , we get - 1 and 5 for the ... Page 337

... letters , a , b , c , etc. , being used to stand for known num- bers or quantities , while the last letters , x , y , z , etc. , stand for unknown numbers or quantities . An equation which contains only one

... letters , a , b , c , etc. , being used to stand for known num- bers or quantities , while the last letters , x , y , z , etc. , stand for unknown numbers or quantities . An equation which contains only one

**unknown letter**is sometimes ... Page 338

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**unknown letter**, and becomes a determinate equation when particular values are given to all the**unknown letters**but one , then we shall call the ( given ) equation an indeterminate equation . Thus , the equation 35y = 7 is an ... Page 339

... letter , from the high- est to the first , enter separately as factors , at the same time that the equation has a ...

... letter , from the high- est to the first , enter separately as factors , at the same time that the equation has a ...

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### Other editions - View all

### Common terms and phrases

algebraic arithmetical progression ascending powers becomes binomial called changing the sign clear clearly coefficients common logarithm compound quantity conse consequently corresponding cube root cx² decimal places denote derived function difference divide dividend division equa equal ratios equal roots evident EXAMPLES exponent expressed extract the square factors find the number follows fraction given equation gives greater greatest common divisor Hence imaginary roots inequality integer least common multiple less logarithm monomial multiplicand multiplier negative roots nth root number of terms numbers or quantities odd number polynomial positive integer positive roots proportion proposed equation quadratic quently quotient real roots remainder remaining roots represent result right member rule second term solution square root subtract supposed surds thence third term tion unknown letter whole number

### Popular passages

Page 374 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.

Page 307 - Multiply the complete divisor by the second term of the root, and subtract the product from the remainder.

Page 152 - A man and his wife usually drank out a cask of beer in 12 days ; but when the man was from, home, it lasted the woman 30 days ; how many days would the man be in drinking it alone ? Ans.

Page 141 - II. Divide the greater number by the less, writing the quotient between the verticals, the product under the dividend, and the remainder below. III. Divide the less number by the remainder, the last divisor by the last remainder, and so on, till nothing remains. The last divisor will be the greatest common divisor sought.

Page 347 - Three lines are in harmonical proportion, when the first is to the third, as the difference between the first and second, is to the difference between the second and third ; and the second is called a harmonic mean between the first and third. The expression 'harmonical proportion...

Page 161 - ... multiply each numerator by all the denominators, except its own, for a new numerator, and under it write the common denominator.

Page 215 - Or, four terms are in harmonical proportion, when the first is to the fourth as the difference of the first and second is to the difference of the third and fourth.

Page 375 - A, B, C, D, E play together on this condition, that he who loses shall give to all the rest as much as they already have. First A loses, then B, then C, then D, and at last also E. All lose in turn, and yet at the end of the 5th game they all have the same sum, viz. each $32. How much had each when they began to play ? Ans.

Page 209 - The first term, the last term (or the extremes) and the ratio given, to find the sum of the series. RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.

Page 173 - ... proportion, the sum of the extremes is equal to the sum of the means. Thus...