An elementary course of practical mathematics, Part 31851 |
Common terms and phrases
acute angle adjacent angle opposite angles of elevation angular Answers applications base called CHAPTER VII circle column common compasses complete Compute contain corresponding Cosec Cosine Cotang course cube decimal point diagram diameter difference direction distance Divide EDINBURGH employed equal EXAMPLE EXERCISES IN CHAPTER factors feet figures foot former four Geometry given given number given side greater half height horizontal hypothenuse inches integers interest latter length less logarithms look marked measured miles minutes Multiply natural number nearly necessary NOTE number of degrees object observed operations Perp perpendicular plane position PRACTICAL preceding Price PROBLEM quadrant questions radius remove right-angled triangle RULE scale Secant seen sextant side Sine stands station Table taken Tang tangent telescope third side Treatise Trigonometry turns unit vertex vertical angle yards
Popular passages
Page 282 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Page 274 - RULE. — Subtract the square of the base from the square of the hypothenuse, and extract the square root of the remainder.
Page 377 - Key to above 60 3. Complete Practical Treatise on the Nature and Use of Logarithms, and on Plane Trigonometry, with Logarithmic and Trigonometrical Tables, . 5 0 4.
Page 245 - To find, then, by logarithms, the fourth term in a proportion, ADD THE LOGARITHMS OF THE SECOND AND THIRD TERMS, AND from the sum SUBTRACT THE LOGARITHM OF THE FIRST TERM.
Page 279 - From D as a center with a radius equal to a, draw an arc intersecting El in F and F'.
Page 292 - ... the angle of reflection is always equal to the angle of incidence, the image for any point can be seen only in the reflected ray prolonged.
Page 279 - Let abc (fig. 1 14) be a spherical triangle, whose sphere has its centre in o, and unity for radius. If now from c, on the plane aob, we let fall the perpendicular cd; from d on ae, bo, the perpendiculars de, df, and draw ce, cf; it would be easy to show that the triangles ceo, cfo are right angles...
Page 278 - To find a side, work the following proportion: — as the sine of the angle opposite the given side is to the sine of the angle opposite the required side, so is the given side to the required side.
Page 243 - BY LOGARITHMS. RULE. FROM the logarithm of the dividend subtract the logarithm of the divisor, and the number answering to the remainder will be the quotient required.
Page 284 - That is, as the base, is to the sum of the two sides; so is the difference of the sides, to the sum of the segments of the base.