| Benjamin Peirce - Algebra - 1837 - 300 pages
...which is consistent with the application of the test. To find the Fourth Term of a Proportion. 64. Problem. Given three terms of a proportion, to find...given mean, and the quotient is the required mean. EXAMPLES. 1. Given the three first terms of a proportion respectively BC A, B, C', find the fourth.... | |
| Benjamin Peirce - Algebra - 1837 - 300 pages
...and the quotient is the required extreme. When the required term is a mean, divide the product of ihe extremes by the given mean, and the quotient is the required mean. EXAMPLES. 1. Given the three first terms of a proportion respectively BC A, B, C; find the fourth.... | |
| Benjamin Peirce - Algebra - 1851 - 294 pages
...form a proportion, we obtain from the preceding test A : C = B : D B : A = D : C B:D = A :C D:C= B:A, &c.; To find the Fourth Term of a Proportion. 88....and the quotient is the required mean. 89. EXAMPLES. 3, ' 1. Given the three first terms of a proportion respectively A, B, C; find the fourth. Ans. —T-.... | |
| Benjamin Peirce - Algebra - 1855 - 308 pages
...of a proportion may be transposed in any way which is consistent with the application of the test. To find the Fourth Term of a Proportion. 88. Problem....the three first terms of a proportion respectively rtr* A,B,C, find the fourth. Ans. D-. A 2. Given the three first terms of a proportion respectively... | |
| Benjamin Peirce - Algebra - 1855 - 296 pages
...of a proportion may he transposed in any way which is consistent with the application of the test. To find the Fourth Term of a Proportion. 88. Problem....the three first terms of a proportion respectively SC A,B,C; find the fourth. Ans. -p. A 2. Given the three first terms of a proportion respectively 2... | |
| Cadmus Marcellus Wilcox - Rifle practice - 1859 - 308 pages
...means by the known extreme, the quotient will be the other extreme that we seek. If the fourth unknown term is a mean, divide the product of the extremes by the other, or known mean. In a proportion of this form, 16 : 8 : : 8 : 4, the term 8 is a geometric mean... | |
| Horatio Nelson Robinson - Arithmetic - 1859 - 348 pages
...term be an extreme, divide the product of the means by the given extreme ; if the required farm be a mean, divide the product of the extremes by the given mean. NOTES. 1. If the terms of any couplet be of different denominations, they must be reduced to the same... | |
| Benjamin Peirce - Algebra - 1864 - 298 pages
...D form a proportion, we obtain from the preceding test A :C= B :D B:A = D:C B : D = A : C D:C= B:A, &.c.; To find the Fourth Term of a Proportion. 88....proportion respectively A, B, C; find the fourth. Ans. -j-. BC A 2. Given the three first terms of a proportion respectively 2 a 6 2 , 3 a 2 6, 6 b 3... | |
| Benjamin Peirce - Algebra - 1864 - 314 pages
...of a proportion may be transposed in any way which is consistent with the application of the test. To find the Fourth Term of a Proportion. 88. Problem....required mean. 89. EXAMPLES. 1. Given the three first terns of a proportion respectively ftfi A, B, C; find the fourth. Ans. -j-. A 2. Given the three first... | |
| George Payn Quackenbos - Arithmetic - 1872 - 350 pages
...RULES. — I. To find an extreme, divide the product of the means by the given extreme. II. To find a mean, divide the product of the extremes by the given mean. 452. What is Proportion ? — 453. In how many ways la proportion expressed ? Describe them. — 454.... | |
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