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126 become zero 3d root approximate values coefficient commensurable roots contain continued fraction continued product Corollary courier decimals deficient terms denote derivative dividend equal roots equal to zero Find the 3d Find the continued Find the greatest Find the square Find the sum Free the equation gallons given equation gives greatest common divisor Hence last term least common multiple letter logarithm monomials Multiply negative exponents nth root number of real number of terms Obtain one equation positive roots preceding article Problem proportion quantities in example Questions into Equations quotient radical quantities ratio real roots reduced remainder required equation required number row of signs Scholium Solution Solve the equation square root Sturm's Theorem substitution subtracted suppressed Theorem three equations unity unknown quan unknown quantity whence wine
Page 48 - In any proportion the terms are in proportion by Composition and Division ; that is, the sum of the first two terms is to their difference, as the sum of the last two terms is to their difference.
Page 130 - The rule of art. 28, applied to this case, in which the factors are all equal, gives for. the coefficient of the required power the same power of the given coefficient, and for the exponent of each letter the given exponent added to itself as many times as there are units in the exponent of the required power. Hence...
Page 127 - Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 159 - A certain capital is let at 4 per cent. ; if we multiply the number of dollars in the capital, by the number of dollars in the interest for 5 months, we obtain 11?041§.
Page 172 - Ans. 15 and 26. 31. What two numbers are they, whose sum is a, and the sum of whose squares is b 1 Ans.
Page 232 - An equation of any degree whatever cannot have a greater number of positive roots than there are variations in the signs of Us terms, nor a greater number of negative roots than there are permanences of these signs.
Page 63 - A term may be transposed from one member of an equation to the other by changing its sign.
Page 45 - Given three terms of a proportion, to find the fourth. Solution. The following solution is immediately obtained from the test. When the required term is an extreme, divide the product of the means by the given extreme, and the quotient is the required extreme. When the required term is a mean, divide the product of the extremes by the given mean, and the quotient is the required mean.
Page 196 - Hence, to find the sum, multiply the first term by the difference between unity and that power of the ratio whose exponent is equal to the number of terms, and divide the product by the difference between unity and the ratio. Examples in Geometrical Progression.