Mathematical Questions and Solutions, from the "Educational Times.", Volume 21

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F. Hodgson, 1874
 

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Page 31 - ... and the story ends with the pious exclamation, " from which devill and all other devills defend us, good Lord ! Amen." We have spoken of the collections of tales, which, at the end of the sixteenth and beginning of the seventeenth centuries...
Page 55 - ... p being the perpendicular from the centre of force on the tangent. But in the ellipse, if p, p...
Page 87 - P is y — y' = a(x — a;'), in which a is the tangent of the angle which the tangent at P makes with the axis of x...
Page 89 - Cartesian is equal to twice the area of the circle whose centre is at the triple focus, and which passes through the points of contact of the double tangent...
Page 80 - ... gallons are drawn from the first cask and poured into the second, and the deficiency in the first supplied with с gallons of water.
Page 58 - ... through the centre of the first, prove that the fourth angle will move in a straight line" — Professor JJ Sylvester remarks "this is the admirably simple solution (discovered within the last few years by the French Geometer Peaucellier) of a problem that had generally been supposed as ineffectuable as the quadrature of the circle; and the assumed impossibility of which many...
Page 109 - ... opposite vertex of the given triangle, meet in a point and are equal. 44. On each side of a triangle construct an isosceles triangle with the adjacent angles equal to 30°. Prove that the straight lines joining the outer vertices of these three triangles are equal. LOCI 45. One side and the opposite angle of a triangle are given, and equilateral triangles are constructed on the other two (variable) sides. Find the locus of the middle point of the straight line joining the outer vertices of the...
Page 38 - L'C 42 4199. (Professor Clifford, MA)— Three ternary quadrics U, V, W break up into linear factors 1, 1' ; 2, 2' ; 3, 3
Page 68 - IV. Solution by JL McKENZIE. 1. This theorem is the reciprocal of the following : — " If a line T touch a circle of radius r, and through the point of contact another line L be drawn making with T a constant angle a, the envelope of L is a concentric circle of radius r cosa.
Page 30 - ... agreeing as they should do with the known relation xy = ac + bd : the quadrilateral is thus determined by means of either of its diagonals. It is however interesting to treat the question in a different manner. Considering a, b, c, d, x, y as the sides and diagonals of a quadrilateral, we have between these quantities a given relation, say J!

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