 | Denison Olmsted - Astronomy - 1839 - 306 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the memory.)... | |
 | Denison Olmsted - Astronomy - 1839 - 504 pages
...if A is the middle part, the opposite parts are a and B. Napier's rule is as follows : Radius into the sine of the middle part, equals the product of the tangents of the sdjaeent extremes, or of the cosines of the opposite extremes. (The corresponding vowels arc marked... | |
 | Denison Olmsted - Astronomy - 1839 - 304 pages
...the middle part, the opposite parts are a and B. Napier's rule is as follow* : Radius into the fine of the middle part, equals the product of the tangents of the adjacent extremes, or of the cosines of the opposite extremes. (The corresponding vowels are marked to aid the memory.)... | |
 | Anthony Dumond Stanley - Geometry - 1848 - 134 pages
...next to this and separated by it are called the adjacent parts, and the other two the opposite parts. The SINE of the MIDDLE part, equals the product of the TANGENTS of the ADJACENT parts, and equals the product of the COSINES of the OPPOSITE parts. This proposition may be more easily... | |
 | William Somerville Orr - Science - 1854 - 534 pages
...then it will be found that all the formulas of the last article are included in the following rule. " The sine of the middle part equals the product of the tangents of the adjacent parts, and also equals the product of the cosines of the opposite parts ; " Or, Sin. mid. = tan. ad.... | |
 | Edward Olney - Trigonometry - 1885 - 222 pages
...opposite extremes to comp 0 ? What the adjacent ? To coщр т ? To o? Ion? NAPIER*S RULES118 Hule I- Prop- — In any right angled spherical triangle,...sine of the middle part equals the product of the cosines of the opposite ex\ъ tremesDEM — In the spherical triangle BАC, right angled at A, taking... | |
 | Edward Olney - Geometry - 1872 - 562 pages
...opposite extremes to comp O? What the adjacent? To comp mf To of To n? NAPIER'S RULES. 118, Jlule I. Prop. — In any right angled spherical triangle,...sine of the middle part equals the product of the cosines of the opposite extr ernes. DEM. — In the spherical triangle BAC, right angled at A, taking... | |
 | Edward Olney - Geometry - 1872 - 472 pages
...extremes to comp O ? What the adjacent ? To comp mf To o? To n? F1e. 43. RAPIER'S RULES. 118, Rule I. Prop. — In any right angled spherical triangle,...sine of the middle part equals the product of the cosines of the opposite extremes. DEM. — In the spherical triangle BAC, right angled at A, taking... | |
 | Edward Olney - Geometry - 1879 - 502 pages
...ODE, in either figure, right angled at E. This gives OE = OD x cos DOE, or cos a = cos 6 cos e. (5) 1 19. Rule 2. Prop. — In any right angled spherical triangle, the sine of the middle part equals the produd of the tangents of the adjacent extremes. DEM.— In the spherical triangle BAC, right angled... | |
 | Simon Newcomb - Trigonometry - 1882 - 372 pages
...parts. In the seoond case the adjoining parts are called opposite parts. 111. Napier's rules are : I. The sine of the middle part equals the product of the tangents of the adjacent parts. II. The sine of the middle part equals the product of the cosines of the opposite parts. The... | |
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The sine of the middle part equals the product of the tangents of the adjacent parts. 
