 | John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...divisor. The tum of these three parts will be the complete divisor, which multiply by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next part for a new dividend. Proceed in the same manner as before to find the divisor... | |
 | John Radford Young - Algebra - 1832 - 408 pages
...of the root. Add three times the product of the two terms of the root, plus the square of the last term, to the term already in the divisor's place,...three next terms, and proceed as before. For (by Art. 37), the cube of a + b is a3 + 3a2¿ + 3a62 + ¿3; and, from having the cube given, its root is found... | |
 | Benjamin Peirce - Algebra - 1837 - 302 pages
...to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | Benjamin Peirce - Algebra - 1837 - 300 pages
...to be placed at the right of the divisor. Multiply the divisor, thus augmented, by the last figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the root now found for a new divisor and continue... | |
 | John Radford Young - Algebra - 1838 - 368 pages
...root, plus the square of the last term, to 5 400 + 60 + 8 or 468 3100 + 600 + 40 + 4 or 3744 О"?Л ,1 the term already in the divisor's place, and the divisor...three next terms, and proceed as before. For (by Art. 37,) the cube of a+b is and, from having the cube given, its root is found by the following process,... | |
 | John Radford Young - 1839 - 332 pages
...which will now be completed. Multiply the complete divisor by the term last placed in the quotient, subtract the product from the dividend, and to the remainder connect the two next terms in the compound quantity, and proceed as before ; and so on till all the terms are brought... | |
 | John D. Williams - Algebra - 1840 - 216 pages
...last term, to the terms already in the divisor's place, and the divisor will be complete. Multiply the divisor by the last term of the root, subtract the product from the dividend, and bring iown the next three terms for a dividend, and proceed as before. ™2 „.<! ,jj5 ~.5 db— dc... | |
 | John D. Williams - Algebra - 1840 - 634 pages
...last term, to the terms already in the divisor's place, and the divisor will be complete. Multiply the divisor by the last term of the root, subtract the product from the dividend, and bring down the next three terms for a dividend, and proceed as before. i(aXa)3+3(aX¿)+(*X¿)}=3as-j-3e¿4-eí=the... | |
 | Joseph Bateman - Excise tax - 1840 - 430 pages
...and annex it also to the divisor ; multiply the divisor thus completed by the last figure placed in the root ; subtract the product from the dividend, and to the remainder bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
 | William Foster - 1840 - 92 pages
...term of the root, and place the sum of these results in the divisor. Multiply the divisor thus found by the last term of the root : subtract the product from the remainder, and so on till there is no remainder. PROOF. Since (а+Ьу=а3-\-За*Ь+ЗаР+1г>, the... | |
| |
Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... 
