 | Meteorology - 1829 - 906 pages
...faced at one end, and loaded at the other. Rule. Multiply the number in the table of multiplicands, by the breadth and square of the depth, both in inches,...divide that product by the length, also, in inches; the quotient will be the weight in Jbs.t Example 1. What weight will it require to break a beam of... | |
 | Charles Hutton - Mathematics - 1831 - 656 pages
...transverse Strength of any rectangular Beam of Timber, Jixed at one End and loaded at the other. Rule i. Multiply the value of s, in the preceding table...in inches, and the quotient will be the weight in Iba. This is approximative. Rule. n. 1. Take the ultimate deflection 8 times that of the last problem,... | |
 | Charles Hutton - Mathematics - 1831 - 662 pages
...Centre. . • Ride i. Multiply the tabular value of s by 4 times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Rule u. 1. Compute the ultimate deflection by Prob. v. . square that deflection, and... | |
 | James Hann, Isaac Dodds - Mechanics - 1833 - 234 pages
...Rule. Multiply the value given in the table of data by four times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Example 1. What weight will be necessary to 'break a beam of Canadian oak, the length... | |
 | William Galbraith - Astronomy - 1834 - 454 pages
...Centre. Rule I. — Multiply the tabular value of S by 4 times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for tile weight. Rule II. — 1. Compute the ultimate deflection by Prob. V. ; square that deflection,... | |
 | Andrew Bell - Mathematics - 1842 - 402 pages
...fixed at one end, and loaded at the other. 1 Find the continued product of the tabular value of S, the breadth and square of the depth, both in inches, and divide this product by the length in inches, and the quotient will be the weight in pounds.1 Or, W „ . ld*S... | |
 | James Hann - Mechanics - 1848 - 352 pages
...— Multiply the value given in the table of data by four times the breadth and square of the depth in inches, and divide that product by the length, also in inches, for the weight. Ex. 1. — What weight will be necessary to break a beam of Canadian oak, the length... | |
 | George Beecroft - 1857 - 350 pages
...one end and 1oaded at the other. RULE. — Mu1tipIy the tabuIar va1ue of S, (see TabIe 2, Page 197), by the breadth and square of the depth, both in inches, and divide that product by the 1ength a1so in inches ; the quotient wi11 be the weight in Ibs.t ExampIe I. — What weight wi11 it... | |
 | Andrew Murray - 1861 - 262 pages
...piece of timber fixed at one end and loaded at the other: — RULE. — Multiply the value given in the table of data by the breadth and square of the depth, both in inches, anil divide the product by the length, also in inches ; the quotient will be the breaking weights in... | |
 | Samuel Griffiths - Iron industry and trade - 1873 - 592 pages
...fixed at mic end and loaded at the other. RULE. — Multiply the tabular value of S (see Table 2), by the breadth and square of the depth, both in inches,...and divide that product by the length also in inches ; the quotient will be the weight in Ibs.2 Example I. — What weight will it require to break a beam... | |
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Multiply the number in the table of multiplicands, by the breadth and square of the depth, both in inches, and divide that product by the length, also, in inches; the quotient will be the weight in Jbs.t Example 1. 