 | David Steel - 1805 - 392 pages
...the right hand of the given number, as in division. Subtract the square of this root from the first period ;and to the remainder, annex the next period, for a dividend. Double the root already found, and place it to the left hand of the dividend. Consider, what figure... | |
 | George G. Carey - Arithmetic - 1818 - 602 pages
...the quotient, as in Division, and place iU square under, and subtract 'A from, the above-mentioned period, and to the remainder annex the next period, for a dividend. Double the part of the root already found, and place it on the left of the dividend for a trial divisor,... | |
 | James Thomson (LL.D.) - Arithmetic - 1837 - 296 pages
...contained in it, if it be not a cute tUelf. (3.) Subtract the third power of this figure from the first period, and to the remainder annex the next period for a dividend, and for part of the divisor take 300 times the square of the part of the root already obtained. ^.)... | |
 | Arithmetic - 1843 - 142 pages
...the greatest cube in the left-hand period, put its root in the quotient, subtract the cube from that period, and to the remainder annex the next period for a dividend. Multiply the square of the root by 300 for a divisor, and take it out of the dividend, the quotient... | |
 | James W. Kavanagh - 1846 - 304 pages
...period, enter it under the period, and its root in the quotient place, tahe this 3rd power from the period, and to the remainder annex the next period for a dividend. III. Divide this dividend, omitting the last two figures, by three times the 2nd power of the figure... | |
 | Mathew Wilson - 1854 - 210 pages
...that on the left, and place its root on the right. 3. Subtract this square number from the highest period, and to the remainder annex the next period for a dividend. 4. Double the figure of the root found for a divisor ; find how often it is contained in the dividend,... | |
 | James Stewart Eaton - Arithmetic - 1857 - 376 pages
...greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL DIVISOR ; divide... | |
 | Emerson Elbridge White - Arithmetic (Commercial), 1861 - 1861 - 348 pages
...right as the highest order of the root. 3. Subtract the square of the root figure from the left hand period, and to the remainder annex the next period for a dividend. 4. Double the part of the root already found for a trial divisor, and see how many times it is contained... | |
 | James Stewart Eaton - 1862 - 320 pages
...greatest cube in the left-hand period, place its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by § for a TRIAL DIVISOTJ ;... | |
 | James Stewart Eaton - Arithmetic - 1864 - 322 pages
...greatest cube in the left-hand period, plac» its root as in square root, subtract the cube from the left-hand period and to the remainder annex the next period for a dividend. 3. Square the root figure, annex two ciphers and multiply this result by 3 for a TRIAL DIVISOR ; divide... | |
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Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend. 
