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" ... and place it on the left for a trial divisor. Find how many times the divisor is contained in the dividend, exclusive of the right hand figure, and place the quotient in the root and also on the right of the divisor. 4. Multiply the divisor thus increased,... "
A Concise System of Arithmetic: Peculiarly Adapted to the Use of Schools, in ... - Page 76
by A. Melrose (Teacher) - 1795 - 128 pages
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The shipwright's vade-mecum [by D. Steel].

David Steel - 1805 - 392 pages
...to, or next less than, the dividend. Having found this figure, and its product, subtract the latter from the dividend; to the remainder annex the next period for a new dividend ; then, double the figures already found, for a divisor, ami-proceed as before, till the operation...
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A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - Arithmetic - 1809 - 312 pages
...and likewife on the right hand of the divifor : Multiply the divifor, with the figure laft annexed, by the figure laft placed in the root, and fubtract the product from the dividend : To the the remainder join the next period for a new dividend. 5. Double the figures already found in the root,for...
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The United States Arithmetic: Designed for Academies and Schools

William Vogdes - Arithmetic - 1847 - 324 pages
...in the root. 5. Multiply the sum of these three by the figure last placed in the root, and subtract the product from the dividend ; to the remainder annex...for a new dividend, with which proceed as before. If the given decimal has not as many places as are required, supply them by annexing ciphers. To extract...
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Text-book of arithmetic, for the use of teachers

John Hunter (of Uxbridge.) - 1847 - 266 pages
...divisor, forms the complete divisor. Multiply the complete divisor by the quotient figure; subtract the product from the dividend ; to the remainder annex the next period, for a new dividend; and. for a new trial divisor, either double the quotient, or increase the last complete divisor by...
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Text-book of Arithmetic: For the Use of Teachers : Including All the ...

John Hunter - Arithmetic - 1852 - 184 pages
...divisor, forms the complete divisor. Multiply the complete divisor by the quotient figure ; subtract the product from the dividend ; to the remainder annex the next period, for a new dividend ; and, for a new trial divisor, either double the quotient, or add the last quotient figure to the...
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Stoddard's Practical Arithmetic

John Fair Stoddard - Arithmetic - 1852 - 320 pages
...This sum will be the TRUE DIVISOR, which multiply by the second figure of the root and subtract its product from the dividend. To the remainder annex the next period for a new dividend ; and (treating the two figures in the root as one,) proceed to find a 'new trial divisor as above,...
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Practical Arithmetic, by Induction and Analysis

Joseph Ray - Arithmetic - 1857 - 348 pages
...right of the divisor. 4. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend ; to the remainder annex the next period for a new dividend. t 5. Double the whole root found for a NEW trial divisor, and continue the operation as before, until...
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Practical Arithmetic, by Induction and Analysis

Joseph Ray - Arithmetic - 1857 - 358 pages
...right of the divisor. 4. Multiply the divisor thus increased, by the last ^figure of the root; subtract the product from the dividend ; to the remainder annex the next period for a new dividend. 5. Double the whole root found for a NEW trial divisor, and continue the operation as before, until...
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The Complete Arithmetic

Milton Browning Goff - Arithmetic - 1876 - 462 pages
...first figure of the root. Multiply the resulting divisor by the last figure of the root, and subtract the product from the dividend. To the remainder annex the next period for a new dividend ; and for a divisor double the root already found, and proceed as before, till all the periods are...
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Rider's Little Engineer: A Pocket-book of Engineering and Other Data ...

Joseph Benjamin Rider - Engineering - 1901 - 546 pages
...form the complete divisor. Multiply the complete divisor by the last figure of the root, and subtract the product from the dividend. To the remainder annex the next period, and proceed as before. Find the cube root of 46656. OPERATION. Зб ANALYSIS. — Beginning at units'...
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