Robinson's New Rudiments of Arithmetic |
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Page 34
... SOLUTION . Since there are 5 peaches on one plate , on 3 plates there are 3 times 5 peaches , which are 15 peaches . 3 2. If one peach costs 4 cents , how much will 3 cost ? 3. If 1 orange costs 5 cents , what will 2 oranges cost ? 4 ...
... SOLUTION . Since there are 5 peaches on one plate , on 3 plates there are 3 times 5 peaches , which are 15 peaches . 3 2. If one peach costs 4 cents , how much will 3 cost ? 3. If 1 orange costs 5 cents , what will 2 oranges cost ? 4 ...
Page 37
... SOLUTION . - -As many toys as 5 cents are contained times in 20 cents , which are 4 times . Hence 4 toys can be bought for 20 cents . 6. How many quarts of milk , at 4 cents a quart , can be bought for 16 cents ? 7. To how many boys can ...
... SOLUTION . - -As many toys as 5 cents are contained times in 20 cents , which are 4 times . Hence 4 toys can be bought for 20 cents . 6. How many quarts of milk , at 4 cents a quart , can be bought for 16 cents ? 7. To how many boys can ...
Page 38
... SOLUTION . - As many pears as 3 cents are contained times in 6 cents , which are 2 times . Hence 2 pears can be bought for 6 cents . 6 ÷ 3 = 2 . 6. If 2 pears cost 6 cents , what will 1 pear cost ? SOLUTION . If 2 pears cost 6 cents , 1 ...
... SOLUTION . - As many pears as 3 cents are contained times in 6 cents , which are 2 times . Hence 2 pears can be bought for 6 cents . 6 ÷ 3 = 2 . 6. If 2 pears cost 6 cents , what will 1 pear cost ? SOLUTION . If 2 pears cost 6 cents , 1 ...
Page 40
... SOLUTION . - Since 20 marbles are divided equally among 4 boys , one boy will receive one fourth of 20 marbles , or 5 marbles . 8. If 3 books cost 15 cents , what will 1 book cost ? 9. Write on your slates , in a column , and read , all ...
... SOLUTION . - Since 20 marbles are divided equally among 4 boys , one boy will receive one fourth of 20 marbles , or 5 marbles . 8. If 3 books cost 15 cents , what will 1 book cost ? 9. Write on your slates , in a column , and read , all ...
Page 62
... SOLUTION . - He paid the sum of 6 dollars and 9 dollars , which is 15 dollars . 2. John gave 4 apples to James , 8 to Henry , and 9 to Fred . How many did he give to all ? 3. I gave 7 dollars for a barrel of flour , 5 dollars for a ...
... SOLUTION . - He paid the sum of 6 dollars and 9 dollars , which is 15 dollars . 2. John gave 4 apples to James , 8 to Henry , and 9 to Fred . How many did he give to all ? 3. I gave 7 dollars for a barrel of flour , 5 dollars for a ...
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Common terms and phrases
50 cents 9 cents 9 leaves acres of land annex apples barrels of flour boxes boys broadcloth bushels of corn bushels of wheat butter called cassimere cents a pound ciphers column common denominator contained cords of wood decimal fractions decimal places decimal point dividend division divisor dollars DRY MEASURE eight equal EXAMPLES expressed factors figures that stand five four fractional unit gallons given number grocer bought hogshead horses hundred hundredths improper fraction inches integer less LESSON lowest terms marbles measuring minuend mixed number molasses months multiplicand Multiply nine number is divided OPERATION paid peaches pints quarts Reduce remainder right hand Rule sell seven sheep simple numbers slate SOLUTION square miles Subtract subtrahend tens tenths thousand thousandths TROY WEIGHT whole number worth Write the figures Write the numbers yards of cloth
Popular passages
Page 172 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30j square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Page 83 - The number thus added to itself, or the number to be multiplied, is called the multiplicand. The number which shows how many times the multiplicand is to be taken, or the number by which we multiply, is called the multiplier.
Page 86 - From the preceding examples and illustrations we deduce the following general RULE. I. Write the multiplier under the multiplicand, placing units of the same order under each other. II. Multiply the multiplicand by each figure of the multiplier successively, beginning with the unit figure, and write the first figure of each partial product under the figure of the multiplier used, writing down and carrying as in addition. III. If there are partial products, add them, and their sum will be the product...
Page 179 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 171 - A Gunter's Chain, used by land surveyors, is 4 rods or 66 feet long, and consists of 100 links. TABLE. % 7.92 inches (in.) make 1 link, 1. 25 links " 1 rod, rd. 4 rods, or 66 feet, " 1 chain . .ch. 80 chains
Page 175 - TABLE. 1728 cubic inches (cu. in.) make 1 cubic foot, cu. ft. 27 cubic feet 16 cubic feet 8 cord feet, or 128 cubic feet, 1 cubic yard cu.
Page 150 - RULE. Multiply as in whole numbers, and from the right hand of the product point off as many figures for decimals as there are decimal places in both factors.
Page 178 - DRY MEASURE 2 pints (pt.) = 1 quart (qt.) 8 quarts =1 peck (pk.) 4 pecks = 1 bushel (bu...
Page 104 - Multiply the divisor by this quotient figure, subtract the product from the partial dividend used, and to the remainder bring down the next figure of the dividend. IV. Divide as before, until all the figures of the dividend have been brought down and divided.
Page 176 - A pile of wood 8 feet long, 4 feet wide, and 4 feet high, contains 1 cord; and a cord foot is 1 foot in length of such a pile.