| Abel Flint - Surveying - 1804 - 226 pages
...8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the Sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area.... | |
| Samuel Webber - Mathematics - 1808 - 466 pages
...required the breadth of the street. Ans. 76' 1233335 feet. 414PR0BLEM IV. To find the area of a trapezold. RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and hall" the product will be the area. EXAMPLES. 1. In a trapezoid, the parallel sides are AB 7' 5, and... | |
| Abel Flint - Surveying - 1808 - 190 pages
...the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area.... | |
| Thomas Keith - 1817 - 306 pages
...acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. — 23,... | |
| Abel Flint - Surveying - 1825 - 252 pages
...0.47076=4201 tbe double Area of the Triangle. PROBLEM X. To find the Jbeaof a TrapezoiA. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance, the product will be the Area.... | |
| Zadock Thompson - Arithmetic - 1826 - 176 pages
...the area ? Ans. 54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5 chains... | |
| Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...3600000000 (.60000 36 • • • • 4 • • 00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. EXAMPLE.... | |
| John Gummere - Surveying - 1828 - 404 pages
...80 ch. and the third, N. 25J E. dist. 12.92 ch. : what is the area? Ans. 21 A. 3 R. 2 P. PROBLEM IX. To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by their perpendicular distance, and half the product will be the area.* EXAMPLES. 1.... | |
| Ira Wanzer - Arithmetic - 1831 - 408 pages
...40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the pr«' duct will be the area. Ex. How many square feet are contained in a board which is 12 feet... | |
| Zadock Thompson - Arithmetic - 1832 - 186 pages
...is the area ? Ans. 54.299 rods. 307. To find (he. area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and the... | |
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