## Elements of Euclid Adapted to Modern Methods in Geometry |

### From inside the book

Results 1-5 of 56

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**BC**shall lie wholly on EF ; ( I. Def . 5 , cor . ) hence the bases**BC**and EF are equal . ( Ax . 8. ) And since the triangles have been proved to coincide , the areas are equal ; ( Ax . 8. ) Also , since the**sides**AB and**BC**coincide with ... Page 20

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**side BC**equal to the side EF . It is required to prove that the triangles are equal in every respect . For if the triangle ABC be applied to DEF , so that the point B shall be on E , and BC on EF , then the point C shall be on F , because ... Page 21

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**side**of the base are also equal , namely , the angle DBC equal to the angle ECB . In AB take any point F , and from ...**BC**, and on the same**side**of it , the one triangle must be entirely within the other . For if not , let them stand as ... Page 22

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**side**AB , which is opposite the angle ACB , be equal to the**side**AC , which is opposite the angle ABC . In AB take ...**BC**common to both triangles ; ( Const . ) so that the**sides**DB and**BC**are equal to EC and CB , each to each ; also the ... Page 23

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**BC**along EF , then the point C will coincide with F , since**BC**is equal to EF . Now**BC**coincid- ing with EF , let the tri- A E C CE ΚΑ angle BAC fall on the opposite**side**of EF from the triangle DEF , BA and AC falling as EG and GF ...### Other editions - View all

Elements of Euclid Adapted to Modern Methods in Geometry Euclid,James Bryce,David Munn (F.R.S.E.) No preview available - 1874 |

### Common terms and phrases

AC and CB altitude angle AOB BA and AC bisecting the angle centre chord circles touch circumference cloth coincide Const conv Cor.-Hence diagonal diameter divided draw equal angles equal to BC equal to twice equiangular equilateral triangle Euclid exterior angle Fcap GEOGRAPHY geometrical given circle given line given point given straight line greater half the perimeter Hence hypotenuse inscribed intersecting isosceles triangle less Let ABC LL.D meet middle point multiple opposite sides parallel to BC parallelogram perpendicular polygon produced Proposition Q. E. D. Cor Q. E. D. PROP radius ratio rectangle contained rectilineal figure reflex angle remaining angles required to prove right angles right-angled triangle schol segments shew shewn side BC square on AC tangent THEOREM triangle ABC twice the rectangle twice the square whole line

### Popular passages

Page 68 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.

Page 77 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.

Page 50 - If a parallelogram and a triangle be upon the same base, and between the same parallels; the parallelogram is double of the triangle.

Page 87 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section.

Page 30 - Any two sides of a triangle are together greater than the third side.

Page 204 - Tin; rectangle, contained by the diagonals of a quadrilateral inscribed in a circle, is equal to the sum of the rectangles contained by its opposite sides. Let ABCD be any quadrilateral inscribed in a circle...

Page 89 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square on the other part.

Page 98 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.