 | Benjamin Franklin Foster - Bookkeeping - 1837 - 262 pages
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account ; the quotient is the number of days to be carried back or forward, as the case may require. QJ0 If the balance be... | |
 | Benjamin Franklin Foster - Acceptances - 1837 - 156 pages
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account; the quotient is the number of days to be carried back or forward, as the case may require. (j^r3 If the balance... | |
 | Benjamin Franklin Foster - Accounting - 1837 - 224 pages
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account; the quotient is the number of days to be carried back or forward, as the case may require, ftj" If the balance be... | |
 | Benjamin Franklin Foster - Negotiable instruments - 1843 - 142 pages
...side, as before. Secoud: Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account ; the quotient is the number of days to be carried back or forward, as the case may require. QJ" If the balance be... | |
 | George Nixon Comer - Accounting - 1846 - 122 pages
...equation. Multiply the number of days between the averaged dates by the smallest amount, and divide this product by the balance of the account, the quotient will be the time required for calculation. If the largest amount falls due first, the time is counted back from the... | |
 | George Nixon Comer - Bookkeeping - 1847 - 124 pages
...equation. Multiply the number of days between the averaged dates by the smallest amount, and divide this product by the balance of the account, the quotient will be the time required for calculation. If the largest amount falls due first, the time is counted back from the... | |
 | Rufus Putnam - Arithmetic - 1849 - 402 pages
...of the Dr. and Cr. sides; then multiply the sum first due by the number of days between the dates, and divide the product by the balance of the account ; the quotient will be the equated time in days from the LATEST DATE ; to be reckoned BACKWARD, if the sum last due is the smaller... | |
 | Horace Mann - 1851 - 384 pages
...elapsed from jfhe date of the first bill, and divide the sum of the products by the sum of the bills. To find the equated time for the settlement of an...divide the product by the balance of the account. TJ1e quotient will be the time between the date found for the larger side of the account, and the equated... | |
 | Christopher Columbus Marsh - Bookkeeping - 1851 - 236 pages
...days that intervene between the day on which it is due and the day on which the larger side is due, and divide the product by the balance of the account; the quotient will be the number of days that the balance will be due after or before the date of the larger side. 89 days from... | |
 | Christopher Columbus Marsh - Bookkeeping - 1853 - 156 pages
...of the small side by the number of days that intervene between its date and the date of the larger side, and divide the product by the balance of the account ; the quotient will be the number of days before or after the date of the larger side. Calculation — $400 64 The days that intervene.... | |
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Multiply the amount of the smaller side by the number of days between the two average dates, and divide the product by the balance of the account. The quotient will be the time... 
