| Henry Pearson - Algebra - 1833 - 164 pages
...: 9 Sin TT = 0 : is 6. --0 =cos0: 2 COS 0=1. TT COS - = 0. 2 COS TT = - 1. D TT COS u = sin 9. B Or the sine of an angle is equal to the cosine of its complement, and the cosine of an angle is equal to the sine of its complement. C 7. Sin (TT - 9) = sin 9, cos (TT - 9)... | |
| Mathematics - 1835 - 684 pages
...Also cos. A = — cos. (2л + 1. я- ± A). (27.) Sin. A = ^ = £ p = cos. (D CP) = cos. ( J - A Or the sine of an angle is equal to the cosine of its complement, and vice vend. sin. A sin. (2?r + A) (28.) Tan. A = r- = ]- — —гГ cos. A cos. (-2ir + A) = tan. (2тг... | |
| John Charles Snowball - 1837 - 322 pages
...-/- = sin z ACN = sin (90° - z NC Also, sin z .ДЛС = -— = cos z ACN = cos (90° - z or ¿Ле sine of an angle is equal to the cosine of its complement. In the following pages we shall for the sake of convenience indicate an angle by a single letter, as... | |
| Thomas Grainger Hall - Trigonometry - 1848 - 192 pages
...OP^V is the complement of A. f) -КГ And sin. OPN= = cos. A. PN cos. OPN = =- = sin. -a. and cos. or, the sine of an angle is equal to the cosine of its complement, and the cosine of an angle is equal to the sine of its complement. 17. To prove sin. (— A) = — sin. A ;... | |
| Joseph Allen Galbraith - 1852 - 84 pages
...reason PBC ¡я equal to ACE, and also BC is equal to CE, both being radii ; therefore BP = CQ, ie the sine of an angle is equal to the cosine of its complement ; and CP = EQ, ie the cosine of an angle is equal to the sine of its complement. The following relations... | |
| Joseph Allen Galbraith - 1854 - 146 pages
...is 150° 23'. The following relations exist between the sines and cosines of co1nplemental angles : The sine of an angle is equal to the cosine of its complement. The cosine of an angle is equal to the sine of us complement. Let ACB be any angle, and ACE (fig. 3)... | |
| James Hann - Plane trigonometry - 1854 - 140 pages
...A). Also dividing equation (1) by DP2, we have cot2 A + 1 = cosec2 .•. cosec A = »/(1 + cot' (1) The sine of an angle is equal to the cosine of its complement. '™r> = 9Ql>-A, Since and sin cos ADP = AP - = cos A, sin A ; DP AD that is, sin (90° -A)= cos A,... | |
| Sandhurst roy. military coll - 1859 - 672 pages
...the points of section. MATHEMATICS. — LATIN. (2.) What is the complement of an angle or arc? Prove the sine of an angle is equal to the cosine of its complement. If the sine of an angle is £, what is the cosine, and what the tangent ? p . sin 45° — sin 30°... | |
| Isaac Todhunter - 1860 - 318 pages
...right angle. This restriction however will be no longer retained. We may now shew universally that the sine of an angle is equal to the cosine of its complement, and the cosine of an angle equal to tfte sine of its complement. These propositions may be proved by examining... | |
| Euclides - 1860 - 288 pages
...dividing-both sides by 2 sin. 60°, -sin. '30° = J, but cos. 30° = VI - sin.230° = VI - \ = ^ a And since the sine of an angle is -equal to the cosine of its compliment, , cos. 60° = J, and sin. 60° - —, from which it is easily found that tan. 30° = ~,... | |
| |