 | Charles Hutton - Mathematics - 1811 - 404 pages
...measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 16 Geom.), we have, with respect to the triangle IAP, AIB = p -f- IAP ; and with regard to the... | |
 | Charles Hutton - Mathematics - 1812 - 624 pages
...the measure of ACB, supposing there to be known APB = r, BPC =fi, CP = d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 1 6 Geom.), we have, •with respect to the triangle IAP, AIB = P+IAP; and with regard to the... | |
 | John Gummere - Surveying - 1814 - 398 pages
...the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25° : now in the triangle... | |
 | Olinthus Gregory - Plane trigonometry - 1816 - 278 pages
...measure of ACB, supposing there to be known c , APB = P, BPC = p, CP = d, BC = -LI AC = B. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect- to the triangle IAP, AIB = i> + IAP; and with regard to the triangle BIC, AIB... | |
 | Scottish school-book assoc - 1845 - 444 pages
...find C, the measure of ACB, supposing there to be known APB=P, BPC= p, CP=d, BC=L, AC=R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, (Geo. prop. ] 9), we have, with respect to the triangle IAP, ZAIB=ZP+UAP ; and with regard to the triangle... | |
 | Alexander Ingram - 1851 - 202 pages
...angle ACB. Supposing that APB = P, APC =p; CP = d; AC = C\^ - VP L, and BC = R are known. Since the exterior angle of a triangle is equal to the sum of the two interior and opposite angles ; then the angle AJB = P + IBP, and AIB is also equal to C + CAP ; hence P -f IBP... | |
 | George Roberts Perkins - Geometry - 1856 - 460 pages
...angle ACB of the triangle ACB. THEOREM vI. The exterior angle, formed ly producing one of the sides of a triangle, is equal to the sum of the two interior and opposite aaigles of the triangle. In the. triangle ABC, if the side AB be produced to D, the exterior... | |
 | George Roberts Perkins - Geometry - 1860 - 472 pages
...angle ACB of the triangle ACB. THEOREM VI. The exterior angle, formed by producing one of the sides of a triangle, is equal to the sum of the two interior and opposite angles of the triangle. In the triangle ABC, if the side AB be produced to D, the exterior... | |
 | James Pryde - Navigation - 1867 - 506 pages
...incidence, their complements are also equal ; hence L BAD = L SAF, and L DBC = L GBA. But since the exterior angle of a triangle is equal to the sum of the two interior angles, L. EBC = L ВАС + L. ACB = L. BAD + L DAG + L ACB = L. BAD + L SAF + L ACB = 2 L BAD + L... | |
 | Michigan. Department of Public Instruction - Education - 1893 - 564 pages
...done in the simplest manner you can conceive. GEOMETRY. Demonstrate the following propositions: 1. Any exterior angle of a triangle is equal to the sum of the two opposite interior angles. 2. If the squares of the sides of a quadrilateral are together equivalent... | |
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Any exterior angle of a triangle is equal to the sum of the two opposite interior angles. 
