 The proof, usually given, that the path of a projectile in vacua is a parabola, assumes the equivalent of the equation to a parabola referred to a tangent and the diameter through the point of contact as axes. The following proof * requires only the theorem,...  Proceedings of the Edinburgh Mathematical Society - Page 34by Edinburgh Mathematical Society - 1905Full view - About this book
 | William Holding Echols - Calculus - 1902 - 536 pages
...area, bounded by the curve, the jr-axis, and two ordinates at x0, xt is A = sin GJ I y dx. * Xm. 18. The equation to a parabola referred to a tangent and the diameter through the point of contact is_y* = ix. Show that the area cut off by any chord parallel to the tangent is equal to two thirds... | |
 | Edinburgh Mathematical Society - Electronic journals - 1906 - 494 pages
...The Parabolic Path of a Projectile. The proof, usually given, that the path of a projectile in vacuo is a parabola, assumes the equivalent of the equation...projectile. Let P be the position of the projectile at time Í after the moment of projection ; Vcosa, Vsina the horizontal and vertical components of the initial... | |
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