 | Mathematics - 1801 - 446 pages
...PROBLEM I. Given the first termt the last term, and the ratio, to find tht sum of the series. RULE.* Multiply the last term by the ratio, and from the product subtract the first term, and the remainder, divided by the ratio less I, will give the sum of the series. EXAMPLES. * DEMONSTRATION.... | |
 | Zachariah Jess - Arithmetic - 1810 - 222 pages
...is the last term or greater extreme. Multiply the !ast term by the ratio, from the produft subtraft the first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. - - . EXAMPLE S. - . j Sold 24 yards of Holland, at га.... | |
 | Arithmetic - 1811 - 210 pages
...first term, will give the last term, or greater extreme. > » 2. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio less one for the sum of the series. - EXAMPLES. 1. A thrasher wrought 20 days, and- received... | |
 | Jeremiah Joyce - Arithmetic - 1812 - 274 pages
...determined. I. Given the first term a, the last term z, and the common ratio r, to find the sum s. RULE. Multiply the last term by the ratio, and from the product subtract the first term, and the remainder divided by the ratio, less one, will give the sum of the series ; or — r — 1 Ex.... | |
 | Nathan Daboll - Arithmetic - 1813 - 244 pages
...first term, the last term (or the extremes) and the ratio given, to find the sum of the series RULE. Multiply the last term by the ratio, and from the product subtract the first term ; then divide the remainder by the ratio, less by 1, and the quotient will be the sum of all the terms.... | |
 | Roswell Chamberlain Smith - 1814 - 300 pages
...find Oí* Sum of the Series, we /tare tin: following easy RULE. Multiply the last term, by the ratio, from the product subtract the first term, and divide the remainder by (he ratio, less 1 ; the quotient will be the sum of the eerie« required. « 9. If the extrem« be... | |
 | Arithmetic - 1817 - 214 pages
...the first term, will give the last term, or greater ex treats. 2 Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by ratio Jess (?ae for the sum of the series. EXAMPLE?. 1. A thresher wrought 20 da}-s, and received for... | |
 | Arithmetic - 1818 - 264 pages
...the first term, the last term, (or extremes') and the ra* t|O, to find the sum of the series, RULE. Multiply the last term by the ratio, and from the product subtract the first term, and the rem ainder, divided by the ratio less I, wjif'give the sum of all the terms of the series. EXAMPLES.... | |
 | Phinehas Merrill - Arithmetic - 1819 - 116 pages
...first term, the last term, and the ratio, to find the aggregate or total sum of the series. RULE. — Multiply the last term by the ratio, and from the product subtract the first term, and the remainder, divided by the ratio less one, will give the sum of the whole series. EXAMPLES. 1. The... | |
 | Zachariah Jess - Arithmetic - 1824 - 228 pages
...first term, that product is the last term or greater extreme. Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio less one ; the quotient will be the sum of the series. EXAMPLES. 1 Sold 24 yards of Holland, at 2d. for the... | |
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Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1 ; the quotient will be the sum of the series required. 
