Robinson's New Practical Arithmetic for Common Schools and Academies |
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Page 21
... sold a pig for $ 3 , and a calf for $ 8 . What did he receive for both ? 3. A drover bought 5 sheep of one man , 9 of another , and 3 of another . How many did he buy in all ? 4. How many are 2 and 6 ? 2 and 7 ? 2 and 9 ? 2 and 8 ? 2 ...
... sold a pig for $ 3 , and a calf for $ 8 . What did he receive for both ? 3. A drover bought 5 sheep of one man , 9 of another , and 3 of another . How many did he buy in all ? 4. How many are 2 and 6 ? 2 and 7 ? 2 and 9 ? 2 and 8 ? 2 ...
Page 22
... sold some hay for 102 dollars , six cows for 162 dollars , and a horse for 125 dollars . What did he receive for all ? OPERATION . spanнT Tens . Units . 162 125 Amount , 3 89 SOLUTION . - - We arrange the numbers so that units of like ...
... sold some hay for 102 dollars , six cows for 162 dollars , and a horse for 125 dollars . What did he receive for all ? OPERATION . spanнT Tens . Units . 162 125 Amount , 3 89 SOLUTION . - - We arrange the numbers so that units of like ...
Page 27
... sold them so as to gain $ 695 on each lot . For how much did he sell them ? Ans . $ 17865 . 35. At the battle of Waterloo , which took place June 18 , 1815 , the estimated loss of the French was 40000 men ; of the Prussians , 38000 ; of ...
... sold them so as to gain $ 695 on each lot . For how much did he sell them ? Ans . $ 17865 . 35. At the battle of Waterloo , which took place June 18 , 1815 , the estimated loss of the French was 40000 men ; of the Prussians , 38000 ; of ...
Page 30
... sold 6 of them . How many had he left ? - SOLUTION . Fourteen cows less 6 cows are 8 cows . He had 8 cows left . 2. Stephen , having 9 marbles , lost 4 of them . How many had he left ? 3. If a man earns 10 dollars a week , and spends 6 ...
... sold 6 of them . How many had he left ? - SOLUTION . Fourteen cows less 6 cows are 8 cows . He had 8 cows left . 2. Stephen , having 9 marbles , lost 4 of them . How many had he left ? 3. If a man earns 10 dollars a week , and spends 6 ...
Page 32
... sold them for $ 522. What did he lose ? 20. A man bought a mill for $ 3724 , and sold it for $ 4856 . What did he gain ? Ans . $ 1132 . 21. A drover bought 1566 sheep , and sold 435 of them . How many had he left ? Ans . 1131 sheep . 22 ...
... sold them for $ 522. What did he lose ? 20. A man bought a mill for $ 3724 , and sold it for $ 4856 . What did he gain ? Ans . $ 1132 . 21. A drover bought 1566 sheep , and sold 435 of them . How many had he left ? Ans . 1131 sheep . 22 ...
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Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2009 |
Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2016 |
Common terms and phrases
acres altitude annex annuity barrels of flour base bought bushels ciphers circumference column common denominator common difference common fraction compound interest contained cords cube root cubic decimal point diameter discount dividend division dollars dry measure equal exact divisor EXAMPLES expressed feet figure Find the cost gain gallons geometrical progression given number greatest common divisor Hence hogshead hundred improper fraction inches integers invested last term least common multiple longitude lower denominations measure merchant miles minuend mixed number months multiplicand Multiply number of terms obtain OPERATION paid payment pounds premium prime factors principal proper fraction quotient rate per cent ratio Reduce remainder result rods RULE RULE.-I sells side sold SOLUTION square root subtract subtrahend tens thousand thousandths trial divisor triangle units wheat whole number wide worth write
Popular passages
Page 173 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30j square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Page 180 - DRY MEASURE 2 pints (pt.) = 1 quart (qt.) 8 quarts =1 peck (pk.) 4 pecks = 1 bushel (bu...
Page 185 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 287 - ... for the given number of years. III. Subtract the given principal from the last amount, and the remainder will be the compound interest.
Page 398 - A Cylinder is a body bounded by a uniformly curved surface, its ends being equal and parallel circles.
Page 300 - Thirty days after sight of this first of exchange (second and third of the same tenor and date unpaid...
Page 50 - Division is the process of finding how many times one number is contained in another, or of separating a number into equal parts.
Page 78 - The Greatest Common Divisor of two or more numbers is the greatest number that will exactly divide each of them. Thu4, 18 is the greatest, common divisor of 36 and 54, since it is the greatest number that will divide each of them without a remainder.
Page 308 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments; the quotient will be the average term of credit.
Page 54 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.