Robinson's New Practical Arithmetic for Common Schools and Academies |
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Page 4
... solution , and lastly the rule ; but by the time he reaches the rule he knows it . He could frame it himself in his own way , and should be permitted to do so . The rule might , therefore , be omitted altogether were it not for the fact ...
... solution , and lastly the rule ; but by the time he reaches the rule he knows it . He could frame it himself in his own way , and should be permitted to do so . The rule might , therefore , be omitted altogether were it not for the fact ...
Page 21
... SOLUTION . He gave 5 dollars and 7 dollars , which are 12 dollars . - 2. A farmer sold a pig for $ 3 , and a calf for $ 8 . What did he receive for both ? 3. A drover bought 5 sheep of one man , 9 of another , and 3 of another . How ...
... SOLUTION . He gave 5 dollars and 7 dollars , which are 12 dollars . - 2. A farmer sold a pig for $ 3 , and a calf for $ 8 . What did he receive for both ? 3. A drover bought 5 sheep of one man , 9 of another , and 3 of another . How ...
Page 23
... SOLUTION . Arranging the numbers as in 40 , we first add the column of units , and find the sum to be 17 units , which is 1 ten and 7 units . We write the 7 units in the place of units , and the 1 ten in the place of tens . The sum of ...
... SOLUTION . Arranging the numbers as in 40 , we first add the column of units , and find the sum to be 17 units , which is 1 ten and 7 units . We write the 7 units in the place of units , and the 1 ten in the place of tens . The sum of ...
Page 30
... SOLUTION . Fourteen cows less 6 cows are 8 cows . He had 8 cows left . 2. Stephen , having 9 marbles , lost 4 of them . How many had he left ? 3. If a man earns 10 dollars a week , and spends 6 dollars for provisions , how many dollars ...
... SOLUTION . Fourteen cows less 6 cows are 8 cows . He had 8 cows left . 2. Stephen , having 9 marbles , lost 4 of them . How many had he left ? 3. If a man earns 10 dollars a week , and spends 6 dollars for provisions , how many dollars ...
Page 31
... SOLUTION . We write the less number under the greater , with units under units , tens under tens , etc. , and draw a line underneath . Then , beginning at the right hand , we subtract sepa- rately each figure of the subtrahend from the ...
... SOLUTION . We write the less number under the greater , with units under units , tens under tens , etc. , and draw a line underneath . Then , beginning at the right hand , we subtract sepa- rately each figure of the subtrahend from the ...
Other editions - View all
Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2009 |
Robinson's New Practical Arithmetic for Common Schools and Academies Horatio Nelson Robinson No preview available - 2016 |
Common terms and phrases
acres altitude annex annuity barrels of flour base bought bushels ciphers circumference column common denominator common difference common fraction compound interest contained cords cube root cubic decimal point diameter discount dividend division dollars dry measure equal exact divisor EXAMPLES expressed feet figure Find the cost gain gallons geometrical progression given number greatest common divisor Hence hogshead hundred improper fraction inches integers invested last term least common multiple longitude lower denominations measure merchant miles minuend mixed number months multiplicand Multiply number of terms obtain OPERATION paid payment pounds premium prime factors principal proper fraction quotient rate per cent ratio Reduce remainder result rods RULE RULE.-I sells side sold SOLUTION square root subtract subtrahend tens thousand thousandths trial divisor triangle units wheat whole number wide worth write
Popular passages
Page 173 - Square Measure 144 square inches (sq. in.) = 1 square foot (sq. ft.) 9 square feet = 1 square yard (sq. yd.) 30j square yards = 1 square rod (sq. rd.) 160 square rods = 1 acre (A.) 640 acres = 1 square mile (sq.
Page 180 - DRY MEASURE 2 pints (pt.) = 1 quart (qt.) 8 quarts =1 peck (pk.) 4 pecks = 1 bushel (bu...
Page 185 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 287 - ... for the given number of years. III. Subtract the given principal from the last amount, and the remainder will be the compound interest.
Page 398 - A Cylinder is a body bounded by a uniformly curved surface, its ends being equal and parallel circles.
Page 300 - Thirty days after sight of this first of exchange (second and third of the same tenor and date unpaid...
Page 50 - Division is the process of finding how many times one number is contained in another, or of separating a number into equal parts.
Page 78 - The Greatest Common Divisor of two or more numbers is the greatest number that will exactly divide each of them. Thu4, 18 is the greatest, common divisor of 36 and 54, since it is the greatest number that will divide each of them without a remainder.
Page 308 - Multiply each payment by its term of credit, and divide the sum of the products by the sum of the payments; the quotient will be the average term of credit.
Page 54 - If any partial dividend will not contain the divisor, place a cipher in the quotient, and bring down the next figure of the dividend, and divide as before.