| Robert Simson - Trigonometry - 1806 - 518 pages
...which the vertex of one triangle is upon a side of the other, needs no demonstration. Therefore upon **the same base, and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
| John Playfair - Euclid's Elements - 1806 - 320 pages
...which the vertex of one triangle is upon a side of the other, needs no demonstration. Therefore, upon **the same base, and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
| John Mason Good - 1813 - 722 pages
...subtend, or arc. opposite to» the equal angles, shall be equal to one another. Prop. VII. Theor. Upon **the same base, and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
| Euclides - 1816 - 528 pages
...which the vertex of one triangle is upon a side of the other, needs no demonstration. Therefore, upon **the same base, and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
| Euclid, John Playfair - Circle-squaring - 1819 - 348 pages
...which the vertex of one triangle is upon a side of the other, needs no demonstration.. Therefore, upon **the same base, and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
| Euclides - 1821 - 294 pages
...every equiangular triangle is equilateral ; vide, Elrington. PROP. 7. THEOR. i On the same right line **and on the same side of it there cannot be two triangles** formed whose conterminous sides are equal. If it be possible that there can, 1st, let the vertex of... | |
| Rev. John Allen - Astronomy - 1822 - 508 pages
...it are equal, and therefore the sides opposite to them. PROP. VII. THEOR. Upon the same base (AB), **and on the same side of it, there cannot be two triangles** (ACB, ADB), whose conterminous sides are equal, (namely AC to AD, and BC to BD). For, if possible,... | |
| Peter Nicholson - Mathematics - 1825 - 372 pages
...which the vertex of one triangle is upon a side of the other, needs uo demonstration. Therefore, upon **the same base, and on the same side of it, there cannot be two triangles,** that have their sides which are terminated >n one extremity of the base equal to one another, and likewise... | |
| Robert Simson - Trigonometry - 1827 - 513 pages
...which the vertex of one triangle is upon a side of the other, needs no demonstration. Therefore, upon **the same base, and on the same side of it, there cannot be two triangles** that have thtir sides, which are terminated in one extremity of the base, equal to another, and likewise... | |
| Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - American fiction - 1828 - 598 pages
...angles, the lines AI, BD, produced, will meet.' The other is from Simson's Euclid, prop. 7, b. 1 . ' Upon **the same base and on the same side of it, there cannot be two triangles** that have their sides which are terminated in one extremity of the base equal to one another, and likewise... | |
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