 A pole is fixed on the top of a mound, and the angles of elevation of the top and the bottom of the pole are 60° and 30°, respectively. Prove that the length of the pole is twice the height of the mound.  Plane and Spherical Trigonometry - Page 90by George Albert Wentworth - 1902 - 232 pagesFull view - About this book
 | Samuel H. Winter - 1864 - 348 pages
...perpendicular dropped from the angle с upon the opposite side of a triangle, show that sin с=C- • ab 13. A pole is fixed on the top of a mound, and the angles of elevation of the bottom and top of the pole are 30° and 60° respectively; prove that the height of the pole=twice... | |
 | John Walmsley - Logarithms - 1865 - 232 pages
...from a point 30 feet directly above the former point ; find the height and distance of the steeple. 6. A pole is fixed on the top of a mound, and the angles of elevation of the bottom and top of the pole are 30° and 60° respectively ; prove that the height of the pole is twice... | |
 | James Hamblin Smith - Trigonometry - 1877 - 244 pages
...same angle as a man 6 feet high standing at the base of the column. Find the breadth of the river. (7) A pole is fixed on the top of a mound and the angles of elevation of the top and bottom of the pole are 60° and 30°, shew that the length of the pole is twice the height of the mound.... | |
 | George Albert Wentworth - 1887 - 346 pages
...Show that the height of the tower is a ; the tangent of 18° being V5-1 V(2 + 2V5) V(1Q + 2 V5) 25. A pole is fixed on the top of a mound, and the angles...top and the bottom of the pole are 60° and 30°. Prove that the length of the pole is twice the height of the mound. 26. At a distance (a) from the... | |
 | George Albert Wentworth - 1887 - 206 pages
...the height of the tower is — — ; the tangent of 18° being — ~ — • V(2+2V5) V(1Q + 2V5) 25. A pole is fixed on the top of a mound, and the angles...elevation of the top and the bottom of the pole are 00° and 30°. Prove that the length of the pole is twice the height of the mound. 26. At a distance... | |
 | George Albert Wentworth - Trigonometry - 1888 - 186 pages
...elevation is 18°. Show that the height of the tower is -, the tangent of 18° being V> ' ' V(2+2V5) 25. A pole is fixed on the top of a mound, and the angles...top and the bottom of the pole are 60° and 30°. Prove that the length of the pole is twice the height of the mound. 26. At a distance (a) from the... | |
 | John Maximilian Dyer - Plane trigonometry - 1891 - 306 pages
...Prove that in any triangle ABC ,, . , , a sin В (1) tan A = -^—~ -- =. sin С — a cos В . A (35) A pole is fixed on the top of a mound, and the angles of elevation of the top and bottom of the pole are 60° and 3ÍT. Show that the length of the pole is twice the height of the mound.... | |
 | George Albert Wentworth - Navigation - 1895 - 436 pages
...is 18°. Show that the height of the tower is „ л/г; 1 == ; the tangent of 18° being — -= 25. A pole is fixed on the top of a mound, and the angles...of elevation of the top and the bottom of the pole arc GO0 and 30° respectively. Prove that the length of the pole is twice the height of the mound.... | |
 | George Albert Wentworth - Trigonometry - 1896 - 394 pages
...10 + 2V5 and ¡ — 2V5 _(10+2V5)(6+2V5) 62-(2V5)2 = 5 + 2 V5, cot2 30°= 3. Hence 6 = V2 + 2VВ 25. A pole is fixed on the top of a mound, and the angles of elevation of the top and bottom of the pole are 60° and 30°. Prove that the length of the pole is twice the height of the... | |
 | Great Britain. Civil Service Commission - Civil service - 1896 - 112 pages
...angles A and В of the triangle ABC, when a = 176, b = 135, and С = 47° 30'. 11. A pole is fixed at the top of a mound, and the angles of elevation of the bottom and top of the pole, as seen from the foot of the mound, are 30° and 60°. Find the ratio of... | |
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