## Elements of Geometry and Trigonometry |

### From inside the book

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Page 14

In the first place it is evident that the two lines must coincide entirely between A and B , for othermisa 12 : 2 would be two straight lines between A A B C D and B , which is impossible ( Ax . 11. ) .

In the first place it is evident that the two lines must coincide entirely between A and B , for othermisa 12 : 2 would be two straight lines between A A B C D and B , which is impossible ( Ax . 11. ) .

**Suppose**, however , that on being ... Page 21

D For , if these sides are not equal ,

D For , if these sides are not equal ,

**suppose**AB to be the greater . Then , take BD equal to AC , and draw CD . Now , in the two triangles BDC , BAC , we have BD = AC , by construction ; the angle B equal to the angle ACB ... Page 22

Let us

Let us

**suppose**that we can draw two perpendiculars , AB , AC . Produce either of them , as AB , till BF is equal to AB , and D B E draw FC . Then , the two triangles CAB , . CBF , will be equal : for , the angles CBA , and CBF are right ... Page 23

Let us

Let us

**suppose**BC = BE ; then will the triangle CAB be equal to the the triangle BAE ; for BC = BE , the side AB is common , and the angle CBA = ABE ; hence the sides AC and AE are equal ( Prop . V. Cor . ) ... Page 24

Now , if it be possible ,

Now , if it be possible ,

**suppose**these two sides to be unequal , and that BC is the greater . On BC take BG = EF , and draw AG . Then , in the two triangles BAG , DEF , the angles R and E are equal , being right angles , the side BA ...### What people are saying - Write a review

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### Common terms and phrases

ABCD adjacent altitude angled triangle base become Book called centre chord circle circumference circumscribed common cone consequently contained corresponding Cosine Cotang cylinder described determine diameter difference distance divided draw drawn equal equations equivalent expressed extremities faces feet figure follows formed four frustum give given gles greater half hence homologous hypothenuse included inscribed intersection less logarithm manner means measured meet middle multiplied number of sides opposite parallel parallelogram parallelopipedon pass perpendicular plane polygon prism PROBLEM Prop proportional PROPOSITION pyramid quantities radii radius ratio reason rectangle regular remaining right angles Scholium segment sides similar sine solid solid angle sphere spherical triangle square straight line suppose taken tang tangent THEOREM third triangle triangle ABC unit vertex whole

### Popular passages

Page 18 - If two triangles have two sides of the one equal to two sides of the...

Page 232 - ... the logarithm of a fraction is equal to the logarithm of the numerator minus the logarithm of the denominator.

Page 168 - The radius of a sphere is a straight line drawn from the centre to any point of the surface ; the diameter or axis is a line passing through this centre, and terminated on both sides by the surface.

Page 31 - Hence, the interior angles plus four right angles, is equal to twice as many right angles as the polygon...

Page 18 - America, but know that we are alive, that two and two make four, and that the sum of any two sides of a triangle is greater than the third side.

Page 241 - In every plane triangle, the sum of two sides is to their difference as the tangent of half the sum of the angles opposite those sides is to the tangent of half their difference.

Page 86 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.

Page 168 - CIRCLE is a plane figure bounded by a curved line, all the points of which are equally distant from a point within called the centre; as the figure ADB E.

Page 287 - How many square feet are there in the convex surface of the frustum of a square pyramid, whose slant height is 10 feet, each side of the lower base 3 feet 4 inches, and each side of the upper base 2 feet 2 inches ? Ans.

Page 64 - To inscribe a circle in a given triangle. Let ABC be the given triangle. Bisect the angles A and B by the lines AO and BO, meeting at the point 0.