In the same circle or in equal circles, if two chords are unequally distant from the center, they are unequal, and the chord at the less distance is the greater. Plane Geometry - Page 115by Fletcher Durell - 1904 - 372 pagesFull view - About this book
| Webster Wells - Geometry - 1894 - 256 pages
...OH, or its equal OF, is greater than OG. PROPOSITION XIII. THEOREM. 167. (Converse of Prop. XII.) In the same circle, or in equal circles, if two chords are unequally distant from the centre, the more remote is the less. In the circle ABD, let chord AB be more remote from the centre... | |
| George Washington Hull - Geometry - 1897 - 408 pages
...Therefore AB is farther from the centre than CD. QED PROPOSITION XV. THEOREM. 166. CONVERSELY—In the same circle, or in equal circles, if two chords are unequally distant from the centre, the more remote is the less. Given—The chord AB in the circle ABD farther from the centre... | |
| Henry W. Keigwin - Geometry - 1898 - 250 pages
...distance from 0 than c' is from 0'. [Gen. Ax. [Why? [? [§ 42 (4). [? PROPOSITION XXXII. THEOREM. 163. In equal circles, if two chords are unequally distant from the center, the one at less distance from the center is the greater chord. EXERCISES. 1. Through a given point within... | |
| Webster Wells - Geometry - 1898 - 264 pages
...But, OH>OK. And, OK > OG. (?) PROP. XIII. THEOREM. 167. (Converse of Prop. XII.) In the same cirde, or in equal circles, if two chords are unequally distant from the centre, the more remote is the less. Given 0 the centre of QABC, and chord AB more remote from 0 than... | |
| Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...intersection. EM > EG. (?) EK>EM. (?) Much more is EK > EG. .-. EF>EG. (?) Proposition HO. Theorem. 143. In the same circle, or in equal circles, if two chords are unequally distant from the centre, the chord at the less distance is the greater. Use the indirect method. Ex. 258. The shortest... | |
| Webster Wells - Geometry - 1899 - 424 pages
...OH= OF. (§ 164) But, OH>OK. And, OK> OG. (?) PROP. XIII. THEOREM. 167. (Converse of Prop. XII.) In the same circle, or in equal circles, if two chords are unequally distant from, the centre, the more remote is the less. Given O the centre of OABC, and chord AB more remote from O than... | |
| George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...< OH. § 153 . But OH = OF. § 249 .-.OE<OF. O..ED PROPOSITION VIII. THEOREM. 251. CONVERSELY : In the same circle or in equal circles, if two chords are unequally distant from the centre, they are unequal; and the chord at the less distance is the greater. tig_ In the circle whose... | |
| George Albert Wentworth - Geometry - 1899 - 496 pages
...OF. § 249 .-.OE<OF. QED ARCS, CHORDS, AND TANGENTS. PROPOSITION VIII. THEOREM. 251. CONVERSELY : In the same circle or in equal circles, if two chords are unequally distant from the centre, they are unequal; and the chord at the less distance is the greater. In the circle whose centre... | |
| Education - 1901 - 818 pages
...any transversal they intercept equal parts or every transversal. 2 Prove that in the same circle or equal circles, if two chords are unequally distant from the center, the greater chord is at the less distance. 3 Prove that if from a fixed point without a circle a secant... | |
| Fletcher Durell - Geometry - 1911 - 553 pages
...center). But 05 > OL. Ax. 7. Also 0£ > OF. (Why?) Much more then OR, or its equal OQ > OF. Ax. 12. PROPOSITION X. THEOREM (CONVERSE OF PROP. IX) 228....prove chord CD < chord AB. Proof. Let OH be drawn 1 CD, and OG ± AB. OH > OG. (Why?) On OH mark off OL = OG. Through L let the chord ELF be drawn J_... | |
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