| John Bonnycastle - Algebra - 1811 - 230 pages
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 12. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times theix difference. Ans. 10 and 14. 13. The sum of two numbers i* 8; -uul the... | |
| Charles Hutton - Mathematics - 1811 - 406 pages
...of which the first is to the third as 5 to 9, and the sum of all three is 63. Ans. 1 <, 21, 27. 22. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Charles Hutton - Mathematics - 1812 - 620 pages
...progression, of which the first is to the third as 5 to 9,and the sum of all three is 63? Ans. 15, 21,27. 22. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| John Bonnycastle - Algebra - 1813 - 456 pages
...find a number such, that if you subtract it from 10, and then multiply the remainder by the numbpr itself, the product shall be 21. Ans. 7 or 3 3. It...number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14 4. It is required to divide a line, of 20... | |
| Bewick Bridge - Algebra - 1818 - 254 pages
...18 x (x-yY = 7'2, or (xy)*=4 ; .:xy = 2. Again, x1— and 4xy =96. _12_ .. r~~ > but xy =2; Ex. 6. To divide the number 24 into two such parts, that their product shall, be to thes๎ora of their squares : : 3': 10. ANSWER, 18 and 6. Ex. 7. There are two numbers which are... | |
| Charles Hutton - Arithmetic - 1818 - 646 pages
...which the first is to the third as 5 to 9, and the sum of all three is 63 ? Ans. 15, 21, 27. 22. lt is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Jeremiah Day - Algebra - 1820 - 352 pages
...whose difference, sum, and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their. product shall be to the sum of their squares, as 3 to 1 0. Ans. 1 8 and 6. 13. In a mixture of rum and brandy, the difference... | |
| Bewick Bridge - Algebra - 1821 - 284 pages
...THEOR. 1, 18 x(x— j/)'=72, Again, x*—2xу+у'=4, and 4xy =96. or ж+^=ю,| but x— y=2 ; Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. : ANSWER, 18 and 6. Ex. 7. There are two numbers which are... | |
| John Bonnycastle - Algebra - 1825 - 336 pages
...divide the number 40 into two such. parts, that the sum of their squares shall be 818. Ans. 23 and 1 7. 2. To find a number such, that if you subtract it...length, into two such parts that the rectangle of (he whole and one of the parts shall be equal to the square of the other. Ans. 10^5-10, and 30—10^/5... | |
| Peter Nicholson - Mathematics - 1825 - 1046 pages
...two numbers is 6, and the sum of their 5th power л 105S ; what are the numbers ? Ans. 1 and 4. 21. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 22. A and B. set off at the same time to... | |
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