 The solution of problems of this kind depends upon this principle: Given the product of two factors and one of the factors, the other factor may be found by dividing the product by the given factor, That is, if we know the product of 2 and 5, which is...  Junior High School Mathematics - Page 17by George Wentworth, David Eugene Smith, Joseph Clifton Brown - 1917 - 250 pagesFull view - About this book
 | Education - 1883 - 642 pages
...Refresh the memories of your pupils on the principle, ' 'If the product and either factor be given, the other factor may be found by dividing the product by the factor given." This is important, because from it the so-called second and third cases ot Percentage... | |
 | Education - 1883 - 748 pages
...3. Refresh the memories of your pupils on the principle, "If the product and either factor be given, the other factor may be found by dividing the product by the factor given." This is important, because from it the so-called second and third cases«ot Percentage... | |
 | Education - 1893 - 1072 pages
...Then does he know that when he has the product -of any two factors and one of the factors given, that the other factor may be found by dividing the product by the given factor? Can he recall and apply these universal principles to this particular problem? He is to show by his... | |
 | John William Hopkins - Arithmetic - 1907 - 376 pages
...answer is obtained by multiplying $ 2437 by |, the reciprocal of f . In this problem there are given the product of two factors and one of the factors. The other factor is sought. The problem is therefore one of division. EXERCISE 31 1. Find the price of 78 acres of land... | |
 | John William Hopkins, Patrick Healy Underwood - Arithmetic - 1912 - 406 pages
...answer is obtained by multiplying $2437 by J, the reciprocal of ^. In this problem there are given the product of two factors and one of the factors. The other factor is sought. The problem is therefore one of division. EXERCISE 30 1. Find the price of 78 acres of land... | |
 | George Albert Wentworth, David Eugene Smith - Arithmetic - 1914 - 378 pages
...have learned from the relation 2x5=10, that we can obtain 10 -=- 2 = 5, and 10 + 5 = 2. That is, given the product of two factors, and one of the factors,...found by dividing the product by the given factor, We shall consider a few of these cases before we apply this principle to percentage. ORAL EXERCISE... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1915 - 320 pages
...this will be considered in § 52. The problems in §§ 50 and 52 depend upon this principle: Given the product of two factors and one of the factors,...dividing the product by the given factor. That is, if we know the product of 2 and 5, which is 10, we can find the factor 2 by dividing 10 by 5, and we can... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1915 - 324 pages
...this will be considered in § 52. The problems in §§ 50 and 52 depend upon this principle: Given the product of two factors and one of the factors,...dividing the product by the given factor. That is, if we know the product of 2 and 5, which is 10, we can find the factor 2 by dividing 10 by 5, and we can... | |
 | George Wentworth, David Eugene Smith - Arithmetic - 1915 - 588 pages
...in § 243. The problems in §§ 241 and 243 depend upon this principle: (riven the product of tiro factors and one of the factors, the other factor may...dividing the product by the given factor. That is, if we know the product of 2 and 5, which is 10, we can find the factor 2 by dividing 10 by 5, and we can... | |
 | George Albert Wentworth, David Eugene Smith - Arithmetic - 1920 - 380 pages
...one number is of another. The solution of problems of this kind depends upon this principle : Given the product of two factors and one of the factors,...product by the given factor. That is, if we have given the product 10 and one factor 5, we can find the other factor 2 by dividing 10 by 5; or, if the given... | |
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